<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u></h2>
Find the coordinates of the point which divides the join of (-1,7) and (4,-3) in the ratio 2:3 ?
<h2><u>Solution</u>:-</h2>
Let the given points be A(-1,7) and B(4,-3)
Now,
Let the point be P(x, y) which divides AB in the ratio 2:3
Here,
<h3>

</h3>
Where,
= 2 ,
= 3
= -1 ,
= 4
Putting values we get,
x = 
x = 
x = 
x = 1
Now,
Finding y
<h3>

</h3>
Where,
= 2 ,
= 3
= 7 ,
= -3
Putting values we get,
y = 
y = 
y = 
y = 3
Hence x = 1, y = 3
So, the required point is P(x, y)
= P(1, 3)
<h3>The coordinates of the point is P(1, 3). [Answer]</h3>
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<u>N</u><u>o</u><u>t</u><u>e</u>:- Refer the attachment.
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I think the answer would be 1/10
Here's my work:
Answer : Last option
Tanx =48/80
Tan(angle) = opposite/adjacent
Tanx = 48/80
Complementary angles always equal

do 90 -30 to get 60
the answer is
Use order of operations, or PEMDAS which stands for Parenthesis, Exponent, Division, Addition, and Subtraction.
Do those operations in that order. Can you try?
What will be the first thing you do here, according to PEMDAS?