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Marysya12 [62]
2 years ago
8

Which of the following is equal to the fraction below ? (5/9) ^ 8 A. A. 8(5/9) (5 ^ 8)/(9 ^ 8) B. (5 ^ 8)/9 5/(9 ^ 8)

Mathematics
1 answer:
uysha [10]2 years ago
4 0

Answer:

b

Step-by-step explanation:

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8 0
3 years ago
Please please help if you can it would mean a lot. Thank you!!
zheka24 [161]
11. 6:18 = 1:3
12. 12:48 = 1:4
13. 17:34 = 1:2
14. 8:64 = 1:8

15. 44:4 = 11:1
16. 121:11 = 11:1
17. 12:2 = 6:1
18. 4:2 = 2:1

19. 3:4 and 2:3 = 9:12 and 8:12
20. 1:6 and 3:14 = 7:42 and 9:42
21. 2:7 and 3:5 = 10:35 and 21:35
22. 5:2 and 3:1 = 5:2 and 6:2

Comparing Ratios:

1. 1.7 m = 170 cm
20:170 = 2:17

2. 160:8 = 20:1

3. 15:50 = 3:10

4. For every cup of milk she needs 5 cups of flour, so if she uses 3 cups of milk she'd need 15 cups of flour

Hopefully that helps :)
3 0
2 years ago
Calcula y comprueba las ecuaciones: plisss lo necesito alguien me puede ayudar a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8
vesna_86 [32]

Answer:

a) x=3

b) z=10

c) P= 2

d) X=7

e) U=1

Step-by-step explanation:

Resolver una ecuación consiste en hallar los valores de la variable que hacen cierta la igualdad.

a) 2x= 6

El coeficiente es el número junto a la variable. En este caso, el coeficiente es 2. Para eliminar este número en la expresión 2x, debido a que la variable x esta multiplicada por 2, deberás dividir ambos lados de la ecuación entre 2, debido a que la operación opuesta de la multiplicación es la división.

(2x)÷2=6÷2

x= 3

Comprobar la solución de una ecuación se hace al remplazar la variable en una ecuación con el valor de la solución. La solución debería satisfacer la ecuación cuando se ingresa en esta.

En este caso:

2*3= 6

6=6

b) 10 + z= 20

En este caso se debe sumar o restar la constante que se encuentra acompañando a la variable en ambos lados de la ecuación de manera de aislar el término de la variable. En este caso:

10 - 10 + z= 20 -10

z= 10

Comprobación:

10 + z=20

10 + 10=20

20=20

c) P + 9= 11

P +9 - 9= 11 -9

P=2

Comprobación:

2 + 9= 11

11=11

d) 3X + 8 = 29

En este caso, se suma o resta la constante en ambos lados de la ecuación y luego se elimina el coeficiente de la variable mediante la división o multiplicación. Esto es:

3X + 8 - 8= 29 - 8

3X= 21

3X ÷3= 21÷3

X=7

Comprobación:

3*7 + 8=29

21+8=29

29=29

e) 2U + 8= 10

2U + 8 - 8= 10 -8

2U= 2

2U ÷2= 2÷2

U=1

Comprobación:

2*1 + 8= 10

2 + 8= 10

10=10

8 0
2 years ago
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