The Sandhill School carnival sold $44 worth of advance tickets. The carnival organizers will also sell tickets at the door for $
1 answer:
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Answer:
512 student tickets.
Step-by-step explanation:
Let x be number of student tickets and y be number of adult tickets.
We have been given that at Friday's football game 1,294 tickets were sold. We can represent this information as:
We are also told that each student ticket costs $5.00, and each adult ticket costs $8.00 and 1,294 tickets were sold for a total amount of $8,816. We can represent this information as:
From equation (1) we will get,
Substituting this value in equation (2) we will get,
Therefore, 512 student tickets were purchased at Fridays football game.
Answer:
The answer is below
Step-by-step explanation:
a) y=3x-1
The standard equation of a line is given by:
y = mx + c
Where m is the slope of the line and c is the intercept on the y axis.
Given that y=3x-1, comparing with the standard equation of a line, the slope (m) = 3, Two lines with slope a and b are perpendicular if the product of their slope is -1 i.e. ab = -1. Let the line perpendicular to y=3x-1 be d, to get the slope of the perpendicular line, we use:
3 × d = -1
d = -1/3
To find the equation of the perpendicular line passing through (0,0), we use:
To find x if the point P(x, 4) lies on the new line, insert y = 4 and find x:
b) y=1/4 x+2
Given that y=1/4 x+2, comparing with the standard equation of a line, the slope (m) = 1/4. Let the line perpendicular to y=1/4 x+2 be f, to get the slope of the perpendicular line, we use:
1/4 × f = -1
f = -4
To find the equation of the perpendicular line passing through (0,0), we use:
To find x if the point P(x, 4) lies on the new line, insert y = 4 and find x:
Answer:
C
Step-by-step explanation:
The equation of a line is given by
and
slope (m) is given by:
Where (x_1,y_1) are the first set of point in the line and (x_2,y_2) is the second set of point
<em>Let's take 2 points arbitrarily. (0,0) & (25,20)</em>
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<em>Let's plug it and find the equation:</em>
<em></em>
<em>Now</em>
<em></em>
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<em>C is the correct answer.</em>