Answer:
28
Step-by-step explanation:
x=12 and y=3
x=4 and y =1
x=28 and y=7
We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
If g(x) = (8x + 5) + 1, then the correct answers are in bold below
<span>Select each correct answer.
horizontal translation 1 unit left
vertical translation 1 unit down
vertical translation 5 units up
vertical translation 1 unit up
horizontal translation 5 units right
horizontal translation 5 units left</span>
It is $6 more now than before...maybe you were looking for percent increase?
%change=100(final-initial)/initial
%change=100(10-4)/4=150% increase
13 boxes can I get brainliest please ❤️