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stira [4]
2 years ago
8

What is the area of the composite figure

Mathematics
1 answer:
kati45 [8]2 years ago
8 0

To solve this we will divide the given composite figure into three figures. The three figures will be 2 squares and 1 rectangle. Let's find their areas and add them!

\boxed{ \sf \: area \: of \: square =side ^{2}  }

  • Side 3 metre

\rm \implies \: area = 3 ^{2}

\rm \implies9

<em>Thus, The area of 1st square is 9m²...</em>

  • The area of second square will be also 9m², because the sides of both squares are equal.

<h3>Now area of the reactangle⤵️</h3>

  • Length = 6m
  • Breadth = 7+3=10m

\sf \: area \: of \: rectangle = length \times breadtg

\tt \dashrightarrow \: area = 10 \times 3

\tt \dashrightarrow \: area = 30m ^{2}

<em>Thus, The area of rectangle is 30m²....</em>

  • Now, Add area of all the figures to get the total area.

\bf \:total \: area = 9 + 9 + 30 \\   \bf= 48m {}^{2}

<h3><em>Therefore, The total area of the composite figure is 48m²...~</em></h3>
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According to the Bureau of Labor Statistics, citizens remain unemployed for an average of 15.9 weeks before finding their next job (June, 2008). Suppose you want to show that Louisiana has been effective in getting their unemployed back to work sooner. You take a random sample of 50 citizens who were unemployed six months earlier and ask them to report the duration. You find that the average time spent unemployed was 13.4 weeks with a sample standard deviation of the time unemployed is 6.7 weeks.

1 Which of the following statements is the correct alternative hypothesis?

2 The test statistic for testing the hypothesis is

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b. -2.32

c. -2.11

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Answer:

1  

 The  alternative hypothesis  H_a  :  \mu < 15.9

2

The  test statistics z =  -2.64  

Step-by-step explanation:

From the question we are told that

     The population  mean value for time  citizens remain unemployed is  \mu  =  15.9 \  weeks

     The  sample size is  n =  50

     The  sample standard deviation is  6.7 weeks.

      The  sample mean value for time  citizens remain unemployed is  \mu  =  15.9 \  weeks

       

     The  null hypothesis is  H_o  :  \mu \ge 15.9

      The  alternative hypothesis  H_a  :  \mu < 15.9

Generally test statistics is mathematically represented as

       z =  \frac{ \= x  - \mu }{ \frac{s}{\sqrt{n} } }  

=>    z =  \frac{13.4 - 15.9}{\frac{6.7}{\sqrt{50}}}

=>     z =  -2.64  

   

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3 years ago
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