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emmainna [20.7K]
1 year ago
14

Consider the following graph of two functions,S(1) + 8(2)Step 1 of 2: Finds (1) + 8(2)Enable Zoom/Pan8(x) = x2 - 2x - 1S(x) = -x

+1Vio10-310AnewerKaun

Mathematics
1 answer:
kumpel [21]1 year ago
3 0

.Given:

\begin{gathered} f(x)=-x+1 \\ g(x)=x^2-2x-1 \end{gathered}

ToDetermine: The value of

f(1)+g(2)

Solution

\begin{gathered} f(x)=-x+1 \\ f(1)=-1+1 \\ f(1)=0 \end{gathered}\begin{gathered} g(x)=x^2-2x-1 \\ g(2)=(2)^2-2(2)-1 \\ g(2)=4-4-1 \\ g(2)=-1 \\ f(1)+g(2)=0+(-1) \\ f(1)+g(2)=-1 \end{gathered}

Hence, f(1) + g(2) = -1

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Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They
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Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

P = 2

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Required

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So, we have to calculate the probability of picking the same handle. i.e.

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This gives:

P(G_1\ and\ G_2) = P(G_1) * P(G_2)

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P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}

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P(G_1\ and\ G_2) = \frac{3}{10}

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P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}

P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}

P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}

P(P_1\ and\ P_2) = \frac{1}{10}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)

P(Same) = \frac{3}{10} + \frac{1}{10}

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Basile [38]
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This question is confusing. Please help me!
patriot [66]

Answer:

C. 490.

Step-by-step explanation:

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Hi

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