<img src="https://tex.z-dn.net/?f=3%201%2F3%20times%204%202%2F5" id="TexFormula1" title="3 1/3 times 4 2/5" alt="3 1/3 times 4 2

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omeli [17]

2 years ago

/5" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Veronika [31]2 years ago

6 0

Answer:

86.8 or 434/5

Step-by-step explanation:

31/3 *42/5

divide common factors

31/1 *14/5

multiply numerators and the denominator

31*14/1*5

434/5 or 868

frutty [35]2 years ago

4 0

Answer:

86.8 what form do u want this answer?

Step-by-step explanation:

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3 years ago

Two boats leave the same place at the same time. The first boat heads due north at 10 kilometers per hour. The second boat heads

Maksim231197 [3]

Answer:

18.87 km/hr

Step-by-step explanation:

First boat is heading North with a speed of 10 km/hr.

Second boat is heading West with a speed of 16 km/hr.

Time for which they move = 2.5 hours

To find:

The speed at which the distance is increasing between the two boats.

Solution:

Let the situation be represented by the attached diagram.

Their initial position is represented by point O from where they move towards point A and point B respectively.

$Distance = Speed \times Time$

$Distance\ OA = 10 \times 2.5 = 25\ km$

$Distance\ OB = 16 \times 2.5 = 40\ km$

We can use Pythagorean Theorem to find the distance AB.

AB is the hypotenuse of the right angled $\triangle AOB$ .

According to Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^2 = 25^2 + 40^2\\\Rightarrow AB^2 = 2225^2\\\Rightarrow AB^2 \approx 47.17\ km$

The speed at which distance is increasing between the two boats is given as:

$\dfrac{47.17}{2.5} \approx 18.87\ km/hr$

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2 years ago