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4 years ago

What is the address of the element 14 in Matrix D

Mathematics

2 answers:

MAXImum [283]4 years ago

6 0

Answer:

A.)D23

Step-by-step explanation:

mafiozo [28]4 years ago

3 0

Answer:

The address of the element 14 in matrix D is d23 (First option)

Step-by-step explanation:

The address of an element of Matrix D is written as dfc, where "f" is the number of the row the element belongs and "c" is the number of the column the element belong.

In this case the element 14 is in the second row, then f=2

and it is in the third column, then c=3

Then, the address of the element 14 is dfc=d23

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Answer:

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Step-by-step explanation:

The following equation would be used: $A=\frac{a+b}{2} h$

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3 years ago

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Sedaia [141]

Answer:

Step-by-step explanation:

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3 years ago

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Tatiana [17]

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3 years ago

Read 2 more answers

Use mathematical induction to prove the statement is true for all positive integers n. 1^2 + 3^2 + 5^2 + ... + (2n-1)^2 = (n(2n-

Charra [1.4K]

Answer:

The statement is true is for any $n\in \mathbb{N}$ .

Step-by-step explanation:

First, we check the identity for $n = 1$ :

$(2\cdot 1 - 1)^{2} = \frac{2\cdot (2\cdot 1 - 1)\cdot (2\cdot 1 + 1)}{3}$

$1 = \frac{1\cdot 1\cdot 3}{3}$

$1 = 1$

The statement is true for $n = 1$ .

Then, we have to check that identity is true for $n = k+1$ , under the assumption that $n = k$ is true:

$(1^{2}+2^{2}+3^{2}+...+k^{2}) + [2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)}{3} +[2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot [2\cdot (k+1)-1]^{2}}{3} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot (2\cdot k +1)^{2} = (k+1)\cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$(2\cdot k +1)\cdot [k\cdot (2\cdot k -1)+3\cdot (2\cdot k +1)] = (k+1) \cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$k\cdot (2\cdot k - 1)+3\cdot (2\cdot k +1) = (k + 1)\cdot (2\cdot k +3)$

$2\cdot k^{2}+5\cdot k +3 = (k+1)\cdot (2\cdot k + 3)$

$(k+1)\cdot (2\cdot k + 3) = (k+1)\cdot (2\cdot k + 3)$

Therefore, the statement is true for any $n\in \mathbb{N}$ .

4 0

3 years ago

Explain why you cannot find the intersection points of the two lines shown below. Give both an algebraic reason and a graphical

Art [367]

Answer:

$m_1 = m_2 = 4$

Step-by-step explanation:

Given

$y = 4x + 1$

$y = 4x + 10$

Required

Show that these two lines have no point of intersection

The general equation of a line is

$y = mx + b$

Where m represents slope

In $y = 4x + 1$

$m = 4$

Similarly; in $y = 4x + 10$

$m = 4$

Since the slope of both lines are equal;

$m_1 = m_2 = 4$

This implies that the lines are parallel and parallel lines have no point of intersection

See Attachment for Graph

5 0

3 years ago