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seraphim [82]
2 years ago
15

Create a equation where the solution is x= -5

Mathematics
1 answer:
Illusion [34]2 years ago
5 0

x + 3 = 8

OR

4x - 4 = 16

hope this helps!

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together, jason and mara have $74. jason has $6 more than 1/3 as much money as Mara has. how much does each person have?
alina1380 [7]
Make an equation system based on the problem
<span>Jason and Mara have $74
</span>⇒ j + m = 74
<span> Jason has $6 more than 1/3 as much money as Mara has
</span>⇒ j = (1/3)m + 6
<span>
Then, solve the equation by subtitution
j + m = 74
(1/3)m + 6 + m = 74
(1/3)m + m = 74 - 6
(1/3)m + (3/3)m = 68
(4/3)m = 68
m = 68 </span>÷ 4/3
m = 68 × 3/4
m = 51
Mara has $51

j + m = 74
j + 51 = 74
j = 74 - 51
j = 23
Jason has $23
6 0
3 years ago
Chad's recipe for chocolate chip cookies makes 24 servings of 375 calories each. Chad decided to make 150% of the amount in the
sineoko [7]
The answer is 13,500. I hope this helps
8 0
3 years ago
Keisha, Boris, and Jose sent a total of 126 text messages over their cell phones during the weekend. Boris sent 4 times as many
tangare [24]

Answer:

Boris=504 keisha=120

Step-by-step explanation:

First you would start off by Multiplying 4x126 the result of that is= 504 so thats how much Boris sent. To get the answer to how many jose sent you simply just subtract 6-126 and that should result in 120

5 0
3 years ago
Solve for x <br> Pls help I need this for study guide
frosja888 [35]

Answer:

your study guide can be stuck up you know where :3

4 0
3 years ago
Using addition formula solve tan 15​
salantis [7]

Answer:

2 - \sqrt{3}

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = \frac{tanA-tanB}{1+tanAtanB} and the exact values

tan45° = 1 , tan60° = \sqrt{3} , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= \frac{tan60-tan45}{1+tan60tan45}

= \frac{\sqrt{3}-1 }{1+\sqrt{3} }

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + \sqrt{3} is 1 - \sqrt{3}

= \frac{(\sqrt{3}-1)(1-\sqrt{3})  }{(1+\sqrt{3})(1-\sqrt{3})  } ← expand numerator/denominator using FOIL

= \frac{\sqrt{3}-3-1+\sqrt{3}  }{1-3}

= \frac{-4+2\sqrt{3} }{-2}

= \frac{-4}{-2} + \frac{2\sqrt{3} }{-2}

= 2 - \sqrt{3}

3 0
3 years ago
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