2 years ago

4 consecutive integers add up to 34. Write an equation to find the numbers

Mathematics

1 answer:

Kisachek [45]2 years ago

4 0

Answer:

$(n+(n+1)+(n+2)+(n+3))=34$

Step-by-step explanation:

$(n+(n+1)+(n+2)+(n+3))=34$

To make them consecutive, means they have to be one after the other.
You assume one of the numbers are n, to make the other integers consecutive you add 1 then 2 then 3.

You might be interested in

Simplify the following expression. 4a^-2b A.) b/4a^2 B.)4b/a^2 C.)1/4a^b2

Sergio [31]

ANSWER

The correct answer is B

$\frac{4b}{ {a}^{2} }$

EXPLANATION

The given exponential expression is

$4 {a}^{ - 2} b$

We can rewrite this as,

$4b \times {a}^{ - 2}$

We need to simplify to obtain a positive index, so we apply the following property,

${a}^{ - m} = \frac{1}{ {a}^{m} }$

This implies that,

$4b \times {a}^{ - 2} = 4b \times \frac{1}{ {a}^{2} }$

This will finally simplify to,

$4b \times {a}^{ - 2} =\frac{4b}{ {a}^{2} }$

Therefore the correct answer is B

6 0

3 years ago

Read 2 more answers

Given 2x⁵-6x³-4x²-2x+4 =0 solve for x

saul85 [17]

Answer:

Step-by-step explanation: