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Klio2033 [76]
3 years ago
10

Goods are purchased for ₹1500. If one fifth of the goods sold at a profit of 5% and the remaining four-fifth of the goods at a p

rofit of 10%, find the net profit percentage.
Mathematics
2 answers:
TiliK225 [7]3 years ago
7 0
9%. Step-by-step explanation: 1/5 of 1500 = 300.
Tpy6a [65]3 years ago
6 0

Answer:

9%

Step-by-step explanation:

Cost of 1/5 good = 1500*1/5= 300

Profit= 5%

SP = (profit+100)/100*CP

SP= (5+100)/100*300

SP = 105/100*300

SP= 1.05*300= 315

Cost of 4/5 good = 1500*4/5= 1200

Profit= 10%

SP= (profit+100)/100*CP

SP= (10+100)/100*1200

SP = 110/100*1200

SP= 1.10*1200= 1320

Total SP = 315+1320= 1635

Net profit= 1635-1500= 135

Profit% = 135/1500*100%

Profit% = 0.09*100%

Profit% = 9%

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(9x^4-3x^3+4x^2+5x+7) + (11x^4-4x^2-11x-9)
icang [17]

Answer:

20x^4 - 3x^3 - 6x - 2

5 0
3 years ago
which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater
Nutka1998 [239]

Answer:

\frac{\sqrt[3]{16y^4}}{x^2}

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices \sqrt[n]{a}  = a^{\frac{1}{n}}

So,

\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} } gives

\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}

Also from laws of indices

(ab)^n = a^nb^n

So, the above expression can be further simplified to

\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}

Multiply the exponents gives

\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}

Substitute 2^5 for 32

\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}

\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}

From laws of indices

\frac{a^m}{a^n} = a^{m-n}

This law can be applied to the expression above;

\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})} becomes

2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}

Solve exponents

2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}

2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}

From laws of indices,

a^{-n} = \frac{1}{a^n}; So,

2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}} gives

\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}

The expression at the numerator can be combined to give

\frac{(2y)^{\frac{4}{3}}}{x^2}

Lastly, From laws of indices,

a^{\frac{m}{n} = \sqrt[n]{a^m}; So,

\frac{(2y)^{\frac{4}{3}}}{x^2} becomes

\frac{\sqrt[3]{(2y)}^{4}}{x^2}

\frac{\sqrt[3]{16y^4}}{x^2}

Hence,

\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} } is equivalent to \frac{\sqrt[3]{16y^4}}{x^2}

8 0
3 years ago
sarah competes in a long jump competion. her first jump is 4.25m. her best jump is 12% more than this. however, her best jump is
maxonik [38]
Best jump=4.25+0.12(4.25)=4.76
best jump=75% of winning jump
Winning jump=4.76/75×100=6.35m
5 0
3 years ago
A sphere is cut into 8 congruent pieces. The radius of the
BartSMP [9]

Answer:

64pi cm^2

i think

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A clock has a diameter of 16 inches. How far does the hour hand travel during 5 hours? Use 3.14 for pi.
Karo-lina-s [1.5K]

Therefore the hour hand travels 40.192in in 5 hours

<h3>
How to calculate the area of a sector</h3>

A sector is said to be a part of a circle made of the arc of the circle along with its two radii.

The formula for calculating the area of a sector is expressed as;

A = r²β/2

where

r is the radius of the circle

β is the angle subtended

Since the the hour hand travel during 5 hours, the subtended angle by the sector will be;

β = 360/5

β = 72 degrees

Given the following parameters

r = 16/2

r = 8in

Substitute into the formula

A = 8²(72π)/360
A = 40.192in

Therefore the hour hand travels 40.192in in 5 hours

Learn more on area of a sector here: brainly.com/question/22761976

#SPJ1

8 0
1 year ago
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