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suter [353]
3 years ago
14

When creating an HTML document, what do we use to set aside space for content?

Computers and Technology
1 answer:
Minchanka [31]3 years ago
5 0

Tags are use to set aside space for contents

<h3 /><h3>What is HTML?</h3>

HTML simply means hypertext mark-up language . This is a language for document that are design to be displayed in the web browser.

Tags are HTML codes that defines how a web browser will format and display the content.

The tags is used to set aside space to accommodate contents. Example of tags are header tags(<h1>, <h2>, <h3>, <h4>, <h5> and <h6>), paragraph tag(<p>).

learn more on HTML here: brainly.com/question/9069928

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Write a program that estimates how many years, months, weeks, days, and hours have gone by since Jan 1 1970 by calculations with
Rzqust [24]

Answer:

Explanation:

The following code is written in Java. It uses the LocalDate import to get the number of seconds since the epoch (Jan 1, 1970) and then uses the ChronoUnit import class to transform those seconds into years, months, weeks days, and hours. Finally, printing out each value separately to the console. The output of the code can be seen in the attached picture below.

import java.time.LocalDate;

import java.time.temporal.ChronoUnit;

class Brainly {

   public static void main(String[] args) {

       LocalDate now = LocalDate.now();

       LocalDate epoch = LocalDate.ofEpochDay(0);

       System.out.println("Time since Jan 1 1970");

       System.out.println("Years: " + ChronoUnit.YEARS.between(epoch, now));

       System.out.println("Months: " + ChronoUnit.MONTHS.between(epoch, now));

       System.out.println("Weeks: " + ChronoUnit.WEEKS.between(epoch, now));

       System.out.println("Days: " + ChronoUnit.DAYS.between(epoch, now));

       System.out.println("Hours: " + (ChronoUnit.DAYS.between(epoch, now) * 24));    

   }

}

6 0
3 years ago
You’ve received a tarball called data79.tar from a colleague, but you want to check the names of the files it contains before ex
Nina [5.8K]

Answer:

D. tar rvf data79.tar

4 0
3 years ago
Each peripheral device has its own software, called a(n) ____, which contains the detailed instructions required to start that d
olga nikolaevna [1]
OS or operating system
4 0
3 years ago
You are given a string of n characters s[1 : : : n], which you believe to be a corrupted text document in which all punctuation
alexdok [17]

Answer: provided in the explanation section

Explanation:

Given that:

Assume D(k) =║ true it is [1 : : : k] is valid sequence  words or false otherwise

  • To determine D(n)

now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.

So, from here we have that D(k) is given by the following recorance relation:

D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise

Algorithm:

Valid sentence (s,k)

D [1 : : : k]             ∦ array of boolean variable.

for a ← 1 to m

do ;

d(0) ← false

for b ← 0 to a - j

for b ← 0 to a - j

do;

if D[b] ∧ DICT s([b + 1 : : : a])

d (a) ← True

(b). Algorithm Output

      if D[k] = = True

stack = temp stack           ∦stack is used to print the strings in order

c = k

while C > 0

stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c

P = W (p) - 1

output stack

= 0 =

cheers i hope this helps !!!

8 0
3 years ago
Consider a set of mobile computing clients in a certain town who each
poizon [28]

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - -  cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i  clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we  find the max flow in N

⇒ connecting cl-i clients to  bs-j stations

      like (cl-i, bs-j) = 1

   if f(cl-i, bs-j)  = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected                f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected  to bs-j(stations)   f(cl-i,bs-j) = 1 (o otherwise)

   f(bs-j,t) = no of clients  (cl-i)  connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff    f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

5 0
3 years ago
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