Answer:
- def getLargest(number_list):
- new_list = []
-
- for x in number_list:
- if(isinstance(x, int)):
- new_list.append(x)
-
- largest = max(new_list)
-
- return largest
Explanation:
Firstly, create a function <em>getLargest()</em> that take one input parameter, <em>number_list</em>.
The function will filter out the float type number from the list by using <em>isinstance() </em>method (Line 5). This method will check if a current x value is an integer. If so, the x value will be added to <em>new_list</em>.
Next, use Python built-in <em>max</em> function to get the largest integer from the <em>new_list </em>and return it as output.
Answer:
by building on line presence
Explanation:
If you put yourself out there in multiple social sites you will build a following
Using a linear search to find a value that is stored in the last element of an array of 20,000 elements, 20,000 element(s) must be compared.
Answer:
Random Sampling
Explanation:
Random Sampling technique is being used in the given scenario.