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4 years ago

What is contrast (in Photography)?

Computers and Technology

1 answer:

kozerog [31]4 years ago

3 0

Answer:

Contrast is a tool that photographers use to direct viewers' attention to their subject. There are two types: Tonal Contrast and Color Contrast. TC refers to the difference in tones from the lightest tone to the darkest tone, in other words, the difference in tones from white to gray to black.

Explanation:

heheh there you go

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Practice Home Survey

Ksivusya [100]

Answer:

Since this is a survey without preparation, you can move ahead as you like. However, still, you need to figure out the attributes. Here you need to register plugged in hours for each of your family members. And the same thing is abbreviated as screen time as well. You need to make a table with two columns, a family member's name, and the screen time or plugged in time. And you are not required to do anything else, as the survey is the method of collecting the data. And it does not deal with the analysis. The analysis will be done, when you will sit as an analyst. And in fact, you are making this impromptu survey for the family head, who is in charge of your family which can be your father or mother or your grand father or grand mother. And they can use these details for various findings, like how can they reduce cable TV cost per month, and so on. Your job is to collect the accurate data. And same thing, you need to repeat for all the survey that you are asked to conduct. Always remember, you need to know what data you need to collect through a survey. Plan for the survey only after finding the complete details about this. And even when asked to conduct as unprepared, this knowledge is essential.

Explanation:

Please check the attachment.

5 0

4 years ago

What is the purpose of extent in lines in engineering drawing

Blizzard [7]

Answer:

Extension lines are used to indicate the extension of a surface or point to a location preferably outside the part outline.

Explanation:

7 0

3 years ago

Define an iterative function named append_ordered; it is passed two arguments: a linked list (ll) whose values are ordered from

enot [183]

Answer:

A python programming language (code) was used for this exercise.

The code is shown below in the explanation section

Explanation:

Solution

Python code:

class LN:

def __init__(self,value,next=None):

self.value = value

self.next = next

def list_to_ll(self,l):

if l == []:

return None

front = rear = LN(l[0])

for v in l[1:]:

rear.next = LN(v)

rear = rear.next

return front

def str_ll(self,ll):

answer = ''

while ll != None:

answer += str(ll.value)+'->'

ll = ll.next

return answer + 'None'

def append_ordered(self,ll,v):

ln1=LN(v); #create a node with the new value by creating an instance of the LN class

if ll is None: #if the linked list is empty

ll=ln1 #return the new created node

elif(ll.value >= ln1.value): #if the value to be add is smallest, append the linked list to it

ln1.next=ll

ll=ln1

else:

current=ll; #crate a temporary pointer to iterate over linked list

#iterate till the next node value is smaller than the new value and list is not over

while (current.next is not None and current.next.value < ln1.value):

current=current.next

ln1.next=current.next #save the current node in the next of the new node

current.next=ln1 #save new node in the next of current node

return ll

ln=LN(0); #create an instance of class LN

ll1=ln.list_to_ll([1,2,4,5]); #create a linked list of the list

answer=ln.str_ll(ll1);

print(answer); #print the linked list

ll2=ln.append_ordered(ll1,3); #append the value 3 in the linked list

answer=ln.str_ll(ll2)

print(answer); #print the new linked list

Now,

If Linked list is empty then make the node as head and return it.

If value of the node to be inserted is smaller than value of head node, then insert the node at start and make it head.

In a loop, find the appropriate node after which the input node ( 10 ) is to be inserted.To find the appropriate node start from head,keep moving until you reach a node GN (12 ) who's value is greater than the input node. The node just before GN is the appropriate node (8).