Answer:
The number of boys in the school is;

Explanation:
Given that the ratio of boys to girls in a school is 5:4;

And there are 500 girls in the school.
The number of boys in the school will be;

Therefore, the number of boys in the school is;
Answer:
a. 5177 cm³
b. 3,451 cm³
c. 67%
Step-by-step explanation:
Given:
Diameter of each ball (d) = 13 cm
Radius of the ball (r) = radius of the cylinder = ½(13) = 6.5 cm
Height of the cylinder (h) = the sum of the diameters of the 3 balls = 3(13) = 39 cm
a. Volume of cylinder = πr²h
Plug in the values
Volume of cylinder = π*6.5²*39 = 5176.56 ≈ 5177 cm³
b. Total volume of the three balls = 3(volume of 1 ball) = 3(volume of sphere) = 3(⁴/3πr³)
Plug in the value
Total volume of the 3 balls = 3(⁴/3*π*6.5³) = 3(1150.35) = 3,451.05 ≈ 3,451 cm³
c. % of volume of the container occupied by the 3 balls = total volume of the three balls / volume of cylinder × 100
Plug in the values
= 3,451/5177 × 100
= 66.6602279
≈ 67%
There may be more than one way in which to answer this question. I will assume that the "equation" is a linear one: f(x) = mx + b.
Then (16/3) = m(1) + b
This is one equation in two unknowns, so it does not have a unique solution. Was there more to this problem than you have shared?
If we assume that the y-intercept (b) is zero, then y = mx, and
16/3 = 1m, so that m = 16/3, and so y = (16/3)x.
Answer:
A
Step-by-step explanation:
When Andy walks in you fall
Hello,
100a²-49b²=(10a)²-(7b)²=(10a-7b)(10a+7b)
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