(21gh^4)(6g^6h^2)(3g^2h^6) find the greatest common factor of the monomials

1 answer:

6 0

The answer is
$3g {h}^{2}$
To find greatest common factor, look at the variables: g, h

Look at their coefficients and exponents:
$21g \: \: \: 6 {g}^{6} \: \: \: 3 {g}^{2} \\ {h}^{4} \: \: \: {h}^{2} \: \: \: {h}^{6}$
Find the two groups' GCF:
$3g \\ {h}^{2}$
Combine:
$3g {h}^{2}$

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landon is standing in a hole that is 5.1 ft deep. He throws a rock, and it goes up into the air, out of the hole, and then lands

fredd [130]

Refer to the diagram shown below.

The path of the rock is
y = -0.005x² + 0.4x - 5.1

When x = 0, y = -5.1 ft, which is the location of the hole level.
The rock reaches ground level two times when x = x₁ and when x = x₂.

At ground level, y = 0. Therefore
-0.005x² + 0.4x - 5.1 = 0
Divide through by -0.005.
x² - 82x + 1020 = 0

Solve with the quadratic formula.
x = (82 +/- √(82² - 4*1020))/2
= (82 +/- 51.4198)/2
x = 66.71 or x = 15.29

The smaller value of x is x₁ = 15.3 ft when the rock emerges out of the hole and reaches ground level.
The larger value of x is x₂ = 66.7 ft when the rock falls to the ground.
The rock lands 66.7 ft horizontally from Landon.

Answer: 66.7 ft