<u>Answer:</u>
<u>Step-by-step explanation:</u>
We have a parabola and a small line shown in the graph.
The parabola goes upto x = 2 but does not reach that very value. So x = 2 starts on the line above where x = 2 and ends just before x = 4.
Therefore, this function can be modeled by:
Answer:
5x^2 ( x^2 -2)(x^2 +2)(x^2+2x+2)(x^2-2x+2)
Step-by-step explanation:
5x^10 − 80x^2
The greatest common factor is 5x^2
5x^2 ( x^8 - 16)
Rewriting the parentheses
5x^2 ( x^4 ^2 - 4^2)
We notice the difference of squares (a^2 -b^2) = (a-b)(a+b)
5x^2 ( x^4 -4)(x^4+4)
Again rewriting the first parentheses
5x^2 ( x^2 ^2 -2^2)(x^4+4)
5x^2 ( x^2 -2)(x^2 +2)(x^4+4)
The last term can be rewritten as(x^2+2x+2)(x^2-2x+2)
5x^2 ( x^2 -2)(x^2 +2)(x^2+2x+2)(x^2-2x+2)
Answer:
106.25
Step-by-step explanation:
if u multiply 8.5 by 12.5 then you get 106.25 :)
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