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gavmur [86]
3 years ago
8

I need help extra points and work brainlyisr

Mathematics
1 answer:
arsen [322]3 years ago
8 0

Answer:

106.25

Step-by-step explanation:

if u multiply 8.5 by 12.5 then you get 106.25 :)

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What is the value of the function f(x) = 2x – 5 when x = 22? A17 B49 C105 D39
enyata [817]
<span>f(x) = 2x – 5

</span><span>f(22) = 2(22) – 5 = 44 -5 = 39

answer

</span><span>D39</span>
8 0
3 years ago
Parallelogram PQRS is shown. m/S=(3x), m/R=120, and m/Q=(2y). Find the value of y.A.
fomenos

Option B. From the parallelogram PQRS the value of y is given to be 30

<h3>How to solve for the value of y from the parallelogram</h3>

In order to get the value of y we have to use the formula

2y + 120 = 80

where the value 120 is the angle that is stated as 120 from the question

2y = 180 - 120

2y = 60

y = 60 / 2

y = 30

Hence the value of y = 30

We can go ahead to get the value of x as well

3x + 120 = 180

take the like terms

3x = 180 - 120

3x = 60

divide through by 3 to get x

60 / 3 = x

20 = x

Read more on parallelograms here: brainly.com/question/24056495

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7 0
1 year ago
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Ne4ueva [31]

Answer:

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3 0
3 years ago
Chris shoots an arrow up into the air. The height (in feet) of the arrow is given by the function h(t) = - 16t2 + 64t + 112 wher
iris [78.8K]

Answer:

After 2 seconds

Step-by-step explanation:

First step is find an equation of velocity:

h(t)=-16t2+64t+112. The velocity function is derivated from position function, so we should do that.

v(t)= h´(t)= -16*2*t+64 ⇒ v(t)= -32t+64.

Now we know the arrow reach the maximun height when this velocity is equal to zero when t>0.

0=-32t+64 ⇒ 32t=64, split each member for 32 ⇒ \frac{32t}{32}=\frac{64}{32}

t=2. That means after 2 sec. the arrow reach the maximum height

6 0
3 years ago
Read 2 more answers
Subtract 2xy-8 from 5x^2+3xy+12
JulijaS [17]

Answer:

5x^2 + xy + 20

Step-by-step explanation:

Begin with 5x^2+3xy+12,  Subtracting 2xy yields 5x^2 + xy + 12.  Next, subtracting -8 yields 5x^2 + xy + 12 - (-8), or   5x^2 + xy + 20

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3 years ago
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