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Andreas93 [3]
2 years ago
11

3/10 of a bag of jelly beans 2/10 and of the bag were orange. What fraction of the bag was red and orange

Mathematics
1 answer:
Elden [556K]2 years ago
5 0

Answer:

1/2 of the bag would be red and orange.

Step-by-step explanation:

if 3/10 of the bag was red

and 2/10 was orange, then all you have to do is the add the number of jelly beans that are red and orange,

3/10 + 2/10 is 5/10

simplify and that will get you to 1/2

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The length of a rectangle is 2 ft longer than its width.
notsponge [240]
If the length is 2ft longer than it’s width
Let’s assume width as X and so the length will be X+2
Perimeter=40ft
Putting the values into a equation, we get,
X+2+X=40
=2X+2=40
=2X=38
=X=19
Therefore
Length =X+2=19+2
=21ft
Width=X=19ft
Area of rectangle =lxb
= 21x19
3992ft
HOPE IT WAS HELPFUL :)
6 0
3 years ago
How can I solve this question
Rus_ich [418]
To find the volume of the prism, you need to know the length, height, and width. 
since the length is 4 blocks wide, you can multiply 4 by the length of a single block. 4*1/2 = 4/2. do this for the height and width
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height 7/2
width 3/2
you would then multiply all of them together.
to multiply fractions, just multiply the numerators together and the numerators together

4/2*7/2*3/2 = 84/8
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the answer is C
3 0
3 years ago
What is the quotient of -8x∧6 over 4x∧-3 ??
Allushta [10]

Answer:

-2x^{9} is the quotient

Step-by-step explanation:

We have two expression -8x^6 and 4x^{-3}

We need to find quotient of this expression using exponent law.

First we write as quotient form,

\Rightarrow -\dfrac{8x^6}{4x^{-3}}

\Rightarrow -2x^{6-(-3)}                        (x^m\div x^n=x^{m-n})

\Rightarrow -2x^{6+3}

\Rightarrow -2x^{9}

Thus, -2x^{9} is the quotient of -8x^6 and 4x^{-3}.

8 0
3 years ago
On the first day that tickets to the school play were sold, 100 tickets were sold for $230. Regular tickets cost $3 and student
algol [13]
30 of the $3 tickets were sold
70 of the $2 tickets were sold.

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6 0
4 years ago
Read 2 more answers
X^2-8x+16 divided by ax-4x numerator
Vedmedyk [2.9K]

Answer:

Given:

1). x^2-8x+16 divided by x-4

⇒ \frac{x^2-8x+16}{x-4}

⇒ \frac{x^2-2\times x\times 4+4^2}{x-4}

By factorising numerator by using identity, (a-b)^2=a^2-2\times a \times b +b^2

⇒ \frac{(x-4)^2}{x-4}

⇒ \frac{(x-4)\times(x-4)}{x-4}

⇒ x-4  <u> {Answer}</u>

2). 3x^2y divided by 6xy^2

⇒ \frac{3x^2y}{6xy^2}

⇒\frac{3\times x\times x\times y}{6\times x\times y\times y}

⇒ <u>\frac{x}{2y}</u>  <u>{ Answer}</u>

4 0
4 years ago
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