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elena55 [62]
4 years ago
9

X^2-8x+16 divided by ax-4x numerator

Mathematics
1 answer:
Vedmedyk [2.9K]4 years ago
4 0

Answer:

Given:

1). x^2-8x+16 divided by x-4

⇒ \frac{x^2-8x+16}{x-4}

⇒ \frac{x^2-2\times x\times 4+4^2}{x-4}

By factorising numerator by using identity, (a-b)^2=a^2-2\times a \times b +b^2

⇒ \frac{(x-4)^2}{x-4}

⇒ \frac{(x-4)\times(x-4)}{x-4}

⇒ x-4  <u> {Answer}</u>

2). 3x^2y divided by 6xy^2

⇒ \frac{3x^2y}{6xy^2}

⇒\frac{3\times x\times x\times y}{6\times x\times y\times y}

⇒ <u>\frac{x}{2y}</u>  <u>{ Answer}</u>

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