Question

X^2-8x+16 divided by ax-4x numerator

Answer 1

Answer:

Given:

1). $x^2-8x+16$ divided by $x-4$

⇒ $\frac{x^2-8x+16}{x-4}$

⇒ $\frac{x^2-2\times x\times 4+4^2}{x-4}$

By factorising numerator by using identity, $(a-b)^2=a^2-2\times a \times b +b^2$

⇒ $\frac{(x-4)^2}{x-4}$

⇒ $\frac{(x-4)\times(x-4)}{x-4}$

⇒ $x-4$   {Answer}

2). $3x^2y$ divided by $6xy^2$

⇒ $\frac{3x^2y}{6xy^2}$

⇒$\frac{3\times x\times x\times y}{6\times x\times y\times y}$

⇒ $\frac{x}{2y}$  { Answer}