Answer:
m<4 = 52°
m<BFD = 98°
Step-by-step explanation:
m<1 = (3x)°
m<2 = (5x - 7)°
m<3 = (4x + 15)°
m<AFD = 128°
✔️Find m<4:
m<4 = 180° - m<AFD (angles on a straight line)
Substitute
m<4 = 180° - 128°
m<4 = 52°
✔️m<BFD = m<2 + m<3
Substitute
m<BFD = (5x - 7)° + (4x + 15)°
We need to find the value of x.
Create an equation to find x.
m<1 + m<2 + m<3 = m<AFD (angle addition postulate)
Substitute
3x + 5x - 7 + 4x + 15 = 128°
Add like terms and solve for x
12x + 8 = 128
12x + 8 - 8 = 128 - 8
12x = 120
12x/12 = 120/12
x = 10
m<BFD = (5x - 7)° + (4x + 15)°
Plug in the value of x
m<BFD = 5(10) - 7 + 4(10) + 15
m<BFD = 50 - 7 + 40 + 15
m<BFD = 98°
1/2 is 0.5 The answer is 0.5 because 1/2 is like a half and we know that a this fraction is less than 1. So .5+.5=1 THE ANSWER IS 0.5!
I would say line t !!
it goes through both lines not just one.
71x squared is the answer by finding 7x times 11x then 2x times 3x making 77x = 6x minus 6x from 77x and get 71x squared
Answer:
The Jesse swim fastest
Step-by-step explanation:
Given as :
The distance cover by Elizabeth while swimming = 50 feet
The time taken by Elizabeth = 10 sec
So, Speed of Elizabeth = 
∴ Speed of Elizabeth = 
= 5 feet per sec
Again ,
The distance cover by Jesse while swimming = 110 feet
The time taken by Jesse = 20 sec
So, Speed of Jesse =
∴ Speed of Jesse = 
= 5.5 feet per sec
Again ,
The distance cover by Reagan while swimming = 160 feet
The time taken by Reagan = 30 sec
So, Speed of Reagan =
∴ Speed of Reagan = 
= 5.3 feet per sec
So, 
Hence The Jesse swim fastest Answer
