Question

Please answer!! (look at the picture)

Answer 1

Answer:The word Trigonometry can be broken into the parts Tri, gon, and metry, which means

“Three angle measurement,” or equivalently “Triangle measurement.” Throughout this

unit, we will learn new ways of finding missing sides and angles of triangles which we

would be unable to find using the Pythagorean Theorem alone.

The basic trigonometric theorems and definitions will be found in this portion of the text,

along with a few examples, but the reader will frequently be directed to refer to detailed

“tutorials” that have numerous examples, explorations, and exercises to complete for a

more thorough understanding of each topic.

One comment should be made about our notation for angle measurement. In our study of

Geometry, it was standard to discuss the measure of angle A with the notation m A ∠ . It is

a generally accepted practice in higher level mathematics to omit the measure symbol

(although there is variation from text to text), so if we are discussing the measure of a 20o

angle, for example, we will use the notation ∠ = A 20D

rather than m A∠ = 20D .

Step-by-step explanation: Yw

Answer 2

Answer:

$sinT=\dfrac{O}{H}=\dfrac{6\sqrt{2} }{19}$

$cosT=\dfrac{A}{H}=\dfrac{17}{19}$

$tanT=\dfrac{O}{A}=\dfrac{6\sqrt{2} }{17}$

$sinS=\dfrac{O}{H}=\dfrac{17}{19}$

$cosS=\dfrac{A}{H}=\dfrac{6\sqrt{2} }{19}$

$tanS=\dfrac{O}{A}=\dfrac{17}{6\sqrt{2} }$

Step-by-step explanation:

Trig identities:

$sin(x)=\dfrac{O}{H} \ \ \ \ \ cos(x)=\dfrac{A}{H} \ \ \ \ \ tan(x)=\dfrac{O}{A}$

where

• x = angle
• O = side opposite the angle
• A = side adjacent the angle
• H = hypotenuse

$sinT=\dfrac{O}{H}=\dfrac{6\sqrt{2} }{19}$

$cosT=\dfrac{A}{H}=\dfrac{17}{19}$

$tanT=\dfrac{O}{A}=\dfrac{6\sqrt{2} }{17}$

$sinS=\dfrac{O}{H}=\dfrac{17}{19}$

$cosS=\dfrac{A}{H}=\dfrac{6\sqrt{2} }{19}$

$tanS=\dfrac{O}{A}=\dfrac{17}{6\sqrt{2} }$