Answer:
![\sqrt[5]{13^3} = 13^{\frac{3}{5}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B13%5E3%7D%20%3D%2013%5E%7B%5Cfrac%7B3%7D%7B5%7D%7D)
Step-by-step explanation:
Assuming that the 1/2 is to be distributed; slope would be x or 1 and the y intercept would be -4
Answer:
55%
Step-by-step explanation:
Since 44/80 is 0.55*100 is 55%
Hope this helps !
Please mark as brainliest!
Answer:
a) Because the confidence interval does not include 0 it appears that there
is a significant difference between the mean level of hemoglobin in women and the mean level of hemoglobin in men.
b)There is 95% confidence that the interval from −1.76 g/dL<μ1−μ2<−1.62 g/dL actually contains the value of the difference between the two population means μ1−μ2
c) 1.62 < μ1−μ2< 1.76
Step-by-step explanation:
a) What does the confidence interval suggest about equality of the mean hemoglobin level in women and the mean hemoglobin level in men?
Given:
95% confidence interval for the difference between the two population means:
−1.76g/dL< μ1−μ2 < −1.62g/dL
population 1 = measures from women
population 2 = measures from men
Solution:
a)
The given confidence interval has upper and lower bound of 1-62 and -1.76. This confidence interval does not contain 0. This shows that the population means difference is not likely to be 0. Thus the confidence interval implies that the mean hemoglobin level in women and the mean hemoglobin level in men is not equal and that the women are likely to have less hemoglobin than men. This depicts that there is significant difference between mean hemoglobin level in women and the mean hemoglobin level in men.
b)
There is 95% confidence that the interval −1.76 g/dL<μ1−μ2<−1.62 g/dL actually contains the value of the difference between the two population means μ1−μ2.
c)
If we interchange men and women then
- confidence interval range sign will become positive.
- μ1 becomes the population mean of the hemoglobin level in men
- μ2 becomes the population mean of the hemoglobin level in women
- So confidence interval becomes:
1.62 g/dL<μ1−μ2<1.76 g/dL.
I am not sure about the last two phrases, but here's what I think.
2(n+18)
18(2+n)
