Answer:
That's all I could think that you might need. Finish your question please
Step-by-step explanation:
Together: 13
Andre has 3 more
Given is the function for number of adults who visit fair at day 'd' after its opening, a(d) = −0.3d² + 4d + 9.
Given is the function for number of children who visit fair at day 'd' after its opening, c(d) = −0.2d² + 5d + 11.
Any function f(d) to find excess of children more than adults can be written as follows :-
f(d) = c(d) - a(d).
⇒ f(d) = (−0.2d² + 5d + 11) - (−0.3d² + 4d + 9)
⇒ f(d) = -0.2d² + 0.3d² + 5d - 4d + 11 - 9
⇒ f(d) = 0.1d² + d + 2
Answer:
a. 54.05 Mpbs.
b. 2.745... standard deviations.
c. The z-score is 2.745....
d. The carrier's highest data speed is significantly high.
Step-by-step explanation:
a. The difference between the highest measured data speed and the mean is 72.6 - 18.55 = 54.05 Mbps.
b. The amount of standard deviations of 54.05 Mbps is equal to this value divided by the standard deviations, so we yield 
standard deviations.
c. The z-score is equal to the difference between the mean and a data point in standard deviations, so the z-score is 2.745....
d. 2.745... is not between -2 and 2, so the carrier's highest data speed is not insignificant - so it's significantly high.
Answer:
x=1/2
Step-by-step explanation:
Distribute the 10. it will be 20x-40=100x. Subtract 20x from both sides. it will be 40=80x. Divide by 80 to leave the x by itself. x=40/80...in simplify form....its 1/2
Answer/Step-by-step explanation:
(a) The likelihood function to estimate this probability can be written as:
mat[1000, 9800]p9580(1 - p)420
(b) The value of the maximum likelihood estimate of the probability 0.958(By taking log of expression in (a) above)
(c) when the true probability is 98%, then it implies that 9800 of 10,000 bulbs did last over 6500hours.
Therefore, the likelihood is p(9800) = mat[10000, 9800]p9800(1 - p)200
(d) Method of moments estimate is the estimation of all the parameters of the population sample.
(e) The statement is FALSE because estimates by the method of moments are not necessarily sufficient statistics, because sometimes fail to take into account all relevant information in the sample. As in the above question
