Question

Use the quadratic formula to solve for x.

Answer 1

Answer:

The answer is

$x = \frac{ - 9 - \sqrt{41} }{10} \: \: \: , \: \: \: \: \: \frac{ - 9 + \sqrt{41} }{10}$

Step-by-step explanation:

5x² + 9x + 2 = 0

Using the quadratic formula that's

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a}$

From the question

a = 5 , b = 9 , c = 2

We have

$x = \frac{ - 9 \pm \sqrt{ {9}^{2} - 4(5)(2) } }{2(5)} \\ = \frac{ - 9 \pm \sqrt{81 -40 } }{10} \\ = \frac{ - 9 \pm \sqrt{41} }{10} \: \: \: \: \: \: \: \: \: \:$

We have the final answer as

$x = \frac{ - 9 - \sqrt{41} }{10} \: \: \: , \: \: \: \: \: \frac{ - 9 + \sqrt{41} }{10}$

Hope this helps you