Answer:
t=√d-12/4 and t=√-d-12/4, d≥12
Step-by-step explanation:
Hope this helps.
20)
using
<span>a^3 + b^3 = (a+b)(a^2 − ab + b^2)
</span>so
w^3 + 125z^3
= w^3 +(5z)^3
= (w + 5z)(w^2 - 5wz + 25z^2)
hope it helps
Plug each x-value into the equation to get the y-value:

(2,-1)

(0,-2)