Answer: d) DF ≅ JH
<u>Step-by-step explanation:</u>
Side-Side-Side Congruency Theorem states that triangles are congruent if and only if their corresponding side lengths are congruent.
Given: EF ≅HI
Given: DE ≅IJ
Missing: DF ≅ JH
Recall that for all t,
cos²(t) + sin²(t) = 1
Now,
x = 5 cos(t) - 7 ⇒ (x + 7)/5 = cos(t)
y = 5 sin(t) + 9 ⇒ (y - 9)/5 = sin(t)
so that substituting into the identity above, we get
((x + 7)/5)² + ((y - 9)/5)² = 1
which we can rewrite as
(x + 7)²/25 + (y - 9)²/25 = 1
(x + 7)² + (y - 9)² = 25
and this is the equation of a circle centered at (-7, 9) with radius 5.
.05*2000=100 Non-Sporting
.06*2000=120 Herding
.24*2000=480 Sporting
.21*2000=420 Working
.16*2000=320 Hound
.16*2000=320 Terrier
.12*2000=240 Tay
Hope I didn't mess up for your sake
I pray to hod for yourgood day
