A school needs 1,800 notebooks for next year. If the notebooks come in packages of 90, how many packages should the school buy?

Mathematics

2 answers:

trasher [3.6K]2 years ago

5 0

Answer:

20 packages

Step-by-step explanation:

the school needs 1800 notebooks, since the notebooks come in packages of 90 each. there will be a total of 20 packages.

formula

1800/90

= 20

ipn [44]2 years ago

3 0

Answer:

Step-by-step explanation:

Let x be the number of packs the school should buy.

1800 $\geq$ 90x

/90 /90

20 $\geq$ x

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BlackZzzverrR [31]

Answer:

$y = 8 \: \: \: x = - 10$

Step-by-step explanation:

$4( - 6x - 9y = - 12) \\ 3(8x + 9y = - 8) \\ \: \: \: \: \: \: \\ - 24x - 36y = - 48 \\ 24x + 27y = - 24 \\ \\ - 9y = - 72 \\ y = 8 \\ \\ \\ \\ \\ - 6x - 9y= - 12 \\ - 6x - 72 = - 12 \\ - 6x = - 12 + 72 \\ - 6x = 60 \\ x = - 10$

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2 years ago

Please I'm in urgent need of help. what must be added to make (1/4)x^2-(2/3)xy a perfect square?.

Ipatiy [6.2K]

Answer:

$\bigg(\frac{2}{3} {y} \bigg)^{2}$

STEP BY STEP EXPLANATION

$\frac{1}{4} {x}^{2} - \bigg( \frac{2}{3} \bigg)xy \\ \\ = \bigg(\frac{1}{2} {x} \bigg)^{2} - 2. \bigg(\frac{1}{2} {x} \bigg)\bigg( \frac{2}{3} y \bigg ) + \bigg(\frac{2}{3} {y} \bigg)^{2} \\ \\ = \bigg(\frac{1}{2} {x} - \frac{2}{3} y\bigg)^{2} \\$

To make $\red{\bold{\frac{1}{4} {x}^{2} - \bigg( \frac{2}{3} \bigg)xy}}$ a perfect square we should add $\purple{\bold{\bigg(\frac{2}{3} {y} \bigg)^{2}}}$