<h3>
Answer: Choice A. 82 websites per year</h3>
=============================================================
How I got that answer:
We have gone from 54 websites to 793 websites. This is a change of 793-54 = 739 new websites. This is over a timespan of 2004-1995 = 9 years.
Since we have 739 new websites over the course of 9 years, this means the rate of change is 739/9 = 82.1111... where the '1's go on forever. Rounding to the nearest whole number gets us roughly 82 websites a year.
----------
You could use the slope formula to get the job done. This is because the slope represents the rise over run
slope = rise/run
The rise is how much the number of websites have gone up or down. The run is the amount of time that has passed by. So slope = rise/run = 739/9 = 82.111...
In a more written out way, the steps would be
slope = rise/run
slope = (y2-y1)/(x2-x1)
slope = (793 - 54)/(2004 - 1995)
slope = 739/9
slope = 82.111....
Answer:
Idk
Step-by-step explanation:
Answer:
any score that lies between 88.8 and 97.2 is within one std. dev. of the mean
Step-by-step explanation:
One std. dev. above the mean would be 93 + 4.2, or 97.2. One std. dev. below the mean would be 93 - 4.2, or 88.8.
So: any score that lies between 88.8 and 97.2 is within one std. dev. of the mean.
Answer:
No solutions.
Step-by-step explanation:
x - y = 2 <Start with an equation
x - (x + 2) = 2 <Plug in the given y value and solve for x
x - x - 2 = 2 <Combine like terms
0 - 2 = 2 <There are no values of x
No solutions.
Write a program that uses while loops<span> to perform the following steps: a. ... </span>d. Output all<span> the </span>numbers and their squares between 1 and 10<span>. e.</span>
