A racing car used 255 litres of fuel to complete a 340km race.on average,how many litres of fuel did the car use every 100km?

Solve (-2)-|-13|?????????

Nikitich [7]

-15 hope this helps :0

3 0

2 years ago

2(1 − x) = 9(1 + 2x) + 52(1 − x) = 9(1 + 2x) + 5

marusya05 [52]

Solving the equation $2(1-x) = 9(1 + 2x) + 5$ we get $x=-\frac{3}{5}$

Step-by-step explanation:

We need to solve the equation $2(1-x) = 9(1 + 2x) + 5$ and find value of x

Solving:

$2(1-x) = 9(1 + 2x) + 5\\2-2x=9+18x+5\\Adding\,\,-18x\,\,on\,\,both\,\,sides:\\2-2x-18x=9+5\\Adding\,\,-2\,\,on\,\,both\,\,sides\\-20x=14-2\\-20x=12\\x=\frac{12}{-20}\\x=-\frac{3}{5}$

So, solving the equation $2(1-x) = 9(1 + 2x) + 5$ we get $x=-\frac{3}{5}$

Keywords: Solving Equations

Learn more about Solving Equations at:

#learnwithBrainly

7 0

3 years ago

Evaluate the following limit:

Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

$\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}$

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

By comparison of infinities:

We first expand the binomial squared, so we get

$\large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}$

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

Dividing numerator and denominator by the term of highest degree:

$\large\displaystyle\text{$\begin{gathered}\sf L = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4 }{x^{3}-5 } \end{gathered}$}\\$

$\ \ = \lim_{x \to \infty\frac{\frac{x^{4} }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} } }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}} } }$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} } }{\frac{1}{x}-\frac{5}{x^{4} } } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}$

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

5 0

2 years ago

43. What is the translation rule to map AHIJ to AH ! J'?<br> 11<br> H

lutik1710 [3]

Left 4. Or x-4 because the way it moves

3 0

3 years ago

Find the average.<br><br> 11,16,15,22<br><br> A.64<br> B.15<br> C.17<br> D.16

Artemon [7]

Your answer is D)16. To find the average, add up all the numbers and divivde by the number of numbers there is

7 0

3 years ago

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