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drek231 [11]
2 years ago
7

Mr. Wright has 25 students in his class. More than half of the students

Mathematics
1 answer:
Nadusha1986 [10]2 years ago
3 0

Answer:

x : x<y

Step-by-step explanation:

x = girls

y = boys

Hope it helps

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Choose answer choice a,b,c or d
just olya [345]

Answer:

The answer is A

Step-by-step explanation:

By looking at the graph, the y-intercept is -1. So, the answer must be A or C.

Then we can look at the the graph, you can see the line is left up right down. So the equation will be negative, which is A.

6 0
2 years ago
Hey guys please help with this questoin Find (x+y) ÷ (x-y) if x=5/4 y=-1/3​
pogonyaev

Answer:

<h2>11/19</h2>

Step-by-step explanation:

(\frac{5}{4} + (-\frac{1}{3})) \div (\frac{5}{4} - (-\frac{1}{3}))\\\\\frac{\frac{5}{4}+\left(-\frac{1}{3}\right)}{\frac{5}{4}-\left(-\frac{1}{3}\right)}\\\\\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a,\:-\left(-a\right)=a\\=\frac{\frac{5}{4}-\frac{1}{3}}{\frac{5}{4}+\frac{1}{3}}\\\\\mathrm{Join}\:\frac{5}{4}+\frac{1}{3}:\quad \frac{19}{12}\\\mathrm{Join}\:\frac{5}{4}-\frac{1}{3}:\quad \frac{11}{12}\\\\=\frac{\frac{11}{12}}{\frac{19}{12}}\\\\=\frac{11\times\:12}{12\times \:19}

= 11/19

7 0
3 years ago
If a triangle with vertices A(-1, 4), B(-1, -2), C(2, -2) is dilated with a scale factor of 2 and a center of dilation at the or
givi [52]

Answer:

A' (-2,8) B' (-2,-4) C' (4,-4)

Step-by-step explanation:

Dilations Rule :

(x,y) → (kx,ky)

Scale factor = K

When your scale factor is more than one our triangle gets bigger. When your scale factor is less than one our triangle gets smaller.

( you plug in 2 in every point and those are your answers).

Remember negative times negative is positive and positive times negative is negative.

5 0
2 years ago
PLEASEEEEEEE HELP SOMEONE WHO DOESNT NO MATH
Anuta_ua [19.1K]
No this is not a function because 4 is used twice on the y side
5 0
3 years ago
Read 2 more answers
Divide (- 6 + i)/(1 - 2i) =
Kaylis [27]

~~~\dfrac{(-6 +i)}{(1- 2i)}\\\\\\=\dfrac{(-6+i)(1+2i)}{(1-2i)(1+2i)}\\\\\\=\dfrac{-6-12i+i+2i^2}{1-(2i)^2}\\\\\\=\dfrac{-6-11i-2}{1+4}~~~~~~~~~~~~~;[i^2=-1]\\\\\\=\dfrac{-8-11i}{5}\\\\\\=-\dfrac 85-\dfrac{11}{5}i

4 0
1 year ago
Read 2 more answers
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