Answer:
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Step-by-step explanation:
If 5! is equal to 5 × 4 × 3 × 2 × 1 and 6! is equal to 6 × 5 × 4 × 3 × 2 × 1, then 4! is equal to 4 × 3 × 2 × 1. Thus, 4! = 4 × 3 × 2 × 1, which can simplify to 24. 4! = 24.
is basically 4 × 4 × 4 × 4, which can simplify to 256.
So,
=
.
can simplify to
. Therefore,
=
.
Answer:
Step-by-step explanation:
The room is rectangular in shape. The formula for determining the area of a rectangle is expressed as
Area = length × width
The rectangular hotel room is 3 meters by 5 meters. The area of the room would be
Area = 3 × 5 = 15 square meters
The owner of the hotel wants to re carpet the room with carpet that cost $15.00 per square meter. This means that the cost to re carpet the room would be
15 × 15 = $225
Step-by-step explanation:
Pete has already completed 27 missions. Pete plans to complete 3 missions per week
Let x represents weeks
Games completed = 3x + 27
Sophie has only completed 13 missions. Sophie plans to complete 5 missions per week.
Games completed = 5x + 13
3x + 27 = 5x + 13
27 - 13 = 5x - 3x
2x = 14
x = 7
By the seventh week, they would have completed equal number of games,
Answer:
B
Step-by-step explanation:
2/3 ÷ 1/6
=2/3 × 6/1
sorry if I got it wrong
Answer:
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Step-by-step explanation:
Let s be the number of pages in each issue of the sports magazine, and t be the number of pages in each issue of the technology magazine.
We have been given that Each issue of the sports magazine has 18 fewer pages than each issue of the technology magazine. We can represent this information in an equation as:
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We are also given that sports magazine prints 12 issues per year, so the total number of pages in all the issues of sports magazine will be 12*s.
We are given that a technology magazine prints 10 issues per year, so the total number of pages in all the issues of technology magazine will be 10*s.
Further, the total number of pages in all the issues of the sports magazine for one year is 32 more than the total number of pages in all the issues of the technology magazine for one year.
We can represent this information in an equation as:
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Therefore, our desired system of equations will be:
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