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NeX [460]
2 years ago
6

A support beam needs to be placed at a 28° angle of elevation so that the top meets a vertical beam 1. 6 meters above the horizo

ntal floor. The vertical beam meets the floor at a 90° angle. Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction Approximately how far from the vertical beam should the lower end of the support beam be placed along the horizontal floor? 3. 0 meters 3. 4 meters 3. 9 meters 4. 4 meters.
Mathematics
1 answer:
vlada-n [284]2 years ago
7 0

Answer:

3.0m

Step-by-step explanation:

Place the support beam so the top meets the vertical beam 1.6ms above. You’re gonna need the distance of 3 meters from the support beam.

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catering service offers 8 ​appetizers, 11 main​ courses, and 7 desserts. A banquet committee is to select 7 ​appetizers, 8 main​
guapka [62]

Answer:  The required number of ways is 46200.

Step-by-step explanation:  Given that a catering service offers 8 ​appetizers, 11 main​ courses, and 7 desserts.

A banquet committee is to select 7 ​appetizers, 8 main​ courses, and 4 desserts.

We are to find the number of ways in which this can be done.

We know that

From n different things, we can choose r things at a time in ^nC_r ways.

So,

the number of ways in which 7 appetizers can be chosen from 8 appetizers is

n_1=^8C_7=\dfrac{8!}{7!(8-7)!}=\dfrac{8\times7!}{7!\times1}=8,

the number of ways in which 8 main courses can be chosen from 11 main courses is

n_2=^{11}C_8=\dfrac{11!}{8!(11-8)!}=\dfrac{11\times10\times9\times8!}{8!\times3\times2\times1}=165

and the number of ways in which 4 desserts can be chosen from 7 desserts is

n_3=^7C_4=\dfrac{7!}{4!(7-4)!}=\dfrac{7\times6\times5\times4!}{4!\times3\times2\times1}=35.

Therefore, the number of ways in which the banquet committee is to select 7 ​appetizers, 8 main​ courses, and 4 desserts is given by

n=n_1\times n_2\times n_3=8\times165\times35=46200.

Thus, the required number of ways is 46200.

7 0
4 years ago
1] If 221ₓ= 25₁₀ find X<br> 2] if 3ₓ + 34ₓ - 40ₓ = 0 find x<br> 3] if 23ₓ = 1111₂ find x
Olin [163]

1.

2\cdot x^2+2\cdot x^1+1\cdot x^0=25\\2x^2+2x+1=25\\2x^2+2x-24=0\\x^2+x-12=0\\x^2+4x-3x-12=0\\x(x+4)-3(x+4)=0\\(x-3)(x+4)=0\\x=3 \vee x=-4

The base can't be negative, therefore x=3.

2.

3\cdot x^0+3\cdot x^1+4\cdot x^0-4\cdot x^1+0\cdot x^0=0\\3+3x+4-4x=0\\x=7

3.

2\cdot x^1+3\cdotx^0=1\cdot 2^3+1\cdot2^2+1\cdot2^1+1\cdot2^0\\2x+1=8+4+2+1\\2x=14\\x=7

5 0
2 years ago
A certain spinner has equally sized slices. The probability of landing on a yellow slice is 1/5 . What are the odds in favor of
Paha777 [63]
The correct
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6 0
3 years ago
What is 1 2/3 - 2 1/3?
Zarrin [17]

Answer:

-1/3

Step-by-step explanation:

3 0
3 years ago
What is the surface area of the right cone below?
8_murik_8 [283]

<h2>\red{Solution} \blue \longrightarrow</h2>

Total surface area of cone is 176π

<h3>Explanation:</h3>

Surface area of curved surface of a cone is give by π⋅r.l , where r is the radius and l is the slant height of the cone.

Hence surface area of curved surface of a cone is π×8×14=112π .

As surface area of base is π×82=64π .

Hence total surface area is 112π+64π=176π

8 0
3 years ago
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