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NeX [460]
2 years ago
6

A support beam needs to be placed at a 28° angle of elevation so that the top meets a vertical beam 1. 6 meters above the horizo

ntal floor. The vertical beam meets the floor at a 90° angle. Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction Approximately how far from the vertical beam should the lower end of the support beam be placed along the horizontal floor? 3. 0 meters 3. 4 meters 3. 9 meters 4. 4 meters.
Mathematics
1 answer:
vlada-n [284]2 years ago
7 0

Answer:

3.0m

Step-by-step explanation:

Place the support beam so the top meets the vertical beam 1.6ms above. You’re gonna need the distance of 3 meters from the support beam.

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Shkiper50 [21]

Answer:

I don't really know but one triangle is 180 degrees so two added together is 360 degrees...

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a=c+d (since a+b=180 and c+d+b=180)

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a+e+b+f= the angle sum of quadrilateral PQRS (by substitutions)

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3 years ago
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nirvana33 [79]

Given:

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To find:

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We have,

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Step 1: Substitute f(x)=y .

y=-2x+5

Step 2: Interchange x and y.

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Step 4: Substitute y=g(x).

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Step-by-step explanation:

Given

2b³+5 and b=3 ⇒ 2b³+5=2(3)³+5

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Multiplication

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Addition

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Hope this helps!! :)

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