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SVETLANKA909090 [29]
3 years ago
8

An object has a mass of 18 grams and its volume is 2 cm3 calculate density

Mathematics
2 answers:
Anna [14]3 years ago
6 0
The density is 9 g/cm3
statuscvo [17]3 years ago
5 0

Answer: 9\ gm/cm^3

Step-by-step explanation:

The formula to find the density is given by :-

\text{Density}=\dfrac{\text{Mass}}{\text{Volume}}

Given : Volume of object = 2 cm^3

Mass of object = 18 grams

Then., the density will be :-

\text{Density}=\dfrac{18}{2}=9\ gm/cm^3

Hence, the density of the object would be 9\ gm/cm^3.

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Can you guys help we with this question. ​​​​​​
satela [25.4K]

Answer:

40

Step-by-step explanation:

(2x+1/(2x))^5 *(2x -1/(2x))^5

= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2

= (4x^2-1/4(x)^2)^5

now

x =4x^2. ,a = 1/4(x)^2 ,n =5

we have

general term = Cr *x^r *a^(n-r)

= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)

= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)

= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)

= Cr * 4(2r-n) *x(4r-2n)

now for x^2

4r-2n = 2

4r -10=2

4r =12

r = 3

now for coeff

C(5,3) * 4^(2*3-5)

5!/(3!*(5-3)!) * 4

5*4/(2*1)*4

40

4 0
3 years ago
Read 2 more answers
Lisa's test grades are 79, 89, and 90. there will be one more test this year. if lisa wants her test average to be at least 88,
erik [133]
For this case, what we are going to do first is to assume that all the exams are worth the same percentage of the final grade.
 We have then that Lisa's average grade point equation is:
 88 =  \frac{79 + 89 + 90 + x}{4}
 Where,
 x: minimum note that lisa must obtain in the last exam.
 Clearing x we have:
 x = (88 * 4) - (79 + 89 + 90)

x = 94
 Answer:
 
the lowest grade she can get on her last test is:
 
x = 94
5 0
4 years ago
A ball is projected in to the air. Its height at time t is given by the equation
Ksju [112]
The equation gives the height of the ball. That is, h is the height of the ball. t is the time. Since we are looking for the time at which the height is 8 (h=8), we need to set the equation equal to 8 and solve for t. We do this as follows:

h=-16 t^{2} +60t+1
8=-16 t^{2} +60t+1
16 t^{2} -60t-1+8=0
16 t^{2} -60t+7=0

This is a quadratic equation and as it is set equal to 0 we can solve it using the quadratic formula. That formula is:
t= \frac{-bplus minus \sqrt{ b^{2}-4ac } }{2a}
You might recall seeing this as "x=..." but since our equation is in terms of t we use "t-=..."

In order to use the formula we need to identify a, b and c.
a = the coefficient (number in front of) t^{2} = 16.
b = the coefficient of t = -60
c = the constant (the number that is by itself) = 7

Substituting these into the quadratic formula gives us:
t= \frac{-(-60)plus minus \sqrt{ (-60)^{2}-4(16)(7) } }{2(16)}
t= \frac{60plus minus \sqrt{3600-448 } }{32}
t= \frac{60plus minus \sqrt{3152 } }{32}

As we have "plus minus" (this is usually written in symbols with a plus sign over a minus sign) we split the equation in two and obtain:
t=  \frac{60+56.1426}{32} =3.63
and
t=  \frac{60-56.1426}{32} =.12

So the height is 8 feet at t = 3.63 and t=.12

It should make sense that there are two times. The ball goes up, reaches it's highest height and then comes back down. As such the height will be 8 at some point on the way up and also at some point on the way down.


3 0
3 years ago
B) Write 6.04 * 10 as an ordinary number.
Eddi Din [679]

Answer:

60.4

Step-by-step explanation:

6.04*10=60.4

i hope ti helps you

3 0
3 years ago
Is 0.843 less than 0.846
ioda

Answer:

0.003

Step-by-step explanation:

6-3 =3 and 4-4 = is 0 and 8-8= 0 so the answer is 0.003

5 0
3 years ago
Read 2 more answers
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