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2 years ago

PRETTY please help

Mathematics

2 answers:

lukranit [14]2 years ago

5 0

Answer:

C. 4x − 7

Step-by-step explanation:

Given polynomial:

4x² + x - 14

Find its roots:

x = (- 1 ± √(1 - 4*4*(-14)) / 8
x = (- 1 ± √225) / 8
x = ( -1 ± 15) / 8
x₁ = (- 1 + 15)/ 8 = 14/8 = 7 / 4
x₂ = (- 1 - 15) / 8 = - 16/2 = - 8

The factors:

(x - x₁)(x - x₂) =
(x - 7/4)(x + 8) =
1/4(4x - 7)(x + 8)

Option C is the correct one

Aleksandr [31]2 years ago

3 0

Answer:

The answer is

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)

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PLEASE HELP!!!!! 3, 8, 13, 18, 23, .... The recursive formula for this sequence is:

rodikova [14]

Answer:

a₈ = 37

Step-by-step explanation:

The given arithmetic sequence is: 3, 8, 13, 18, 23, . . .

The recursive formula for the sequence is: $a_n = a_{n - 1} + 5$

Here, $a_n$ represents the $n^{th}$ of the sequence.

And, $a_{n - 1}$ represents the $(n - 1)^{th}$ of the sequence.

'+5' denotes that '5' is added to the $(n - 1)^{th}$ term to get the $n^{th}$ term. In other words, the difference between two consecutive numbers in the sequence is 5.

Now, we are asked to find a₈ i.e., n =8.

Substituting in the recursive formula we get: a₈ = a₍₈₋ ₁₎ + 5 = a₇ + 5.

So, to determine a₈ we need to know a₇. From the sequence we see that a₅ = 23.

⇒ a₆ = 23 + 5 = 28.

⇒ a₇ = 28 + 5 = 32.

⇒ a₈ = 32 + 5 = 37.

Therefore, the $8^{th}$ term of the sequence is 37.

8 0

3 years ago

Identify the correct equation for the graph below.

SashulF [63]

i think it is c

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3 years ago

Another poem i made just now hope yall like it

dolphi86 [110]

Answer:

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Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

The length of a rectangular deck is 4 times its width if the decks perimeter is 30 ft, what is the decks area

omeli [17]

Answer:

The area of the rectangular deck is 36 sq feet.

Step-by-step explanation:

Let the width of the deck = k ft

So, the length of the deck = (4k) ft

Now, perimeter = 30 ft

PERIMETER OF A RECTANGLE = 2(LENGTH + WIDTH)

⇒2( k + 4k) = 30

or, 2 x 5k = 30 ⇒ 10k = 30

⇒ k = 30/10 = 3

So, the width of the deck = k = 3 ft

Length of the deck = 4k = 3 x 4 = 12 ft

Now, AREA OF A RECTANGLE = LENGTH X WIDTH

So, the area of the rectangular deck = 3 ft x 12 ft

= 36 sq feet

Hence, the area of the rectangular deck is 36 sq feet.

8 0

3 years ago

The height of a ball thrown into the air after t seconds have elapsed is h = −16t2 + 40t + 6 feet. What is the first time, t, wh

sp2606 [1]

<h3>The first time when the ball will reach a height of 20 feet is 0.42 seconds</h3>

Solution:

Given that,

The height of a ball thrown into the air after t seconds have elapsed is:

$h = -16t^2 + 40t + 6$

What is the first time, t, when the ball will reach a height of 20 feet?

Substitute h = 20

$20 = -16t^2 + 40t + 6\\\\-16t^2 + 40t + 6 -20 = 0\\\\-16t^2 + 40t -14 = 0\\\\16t^2 -40t + 14 = 0\\\\8t^2 -20t + 7=0$

Solve by quadractic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=8,\:b=-20,\:c=7$

$t = \frac{-\left(-20\right)\pm \sqrt{\left(-20\right)^2-4\cdot \:8\cdot \:7}}{2\cdot \:8}\\\\t = \frac{20 \pm \sqrt{176}}{16}\\\\t = \frac{20 \pm 4\sqrt{11}}{16}\\\\t = \frac{ 5 \pm \sqrt{11}}{4}\\\\We\ have\ two\ solutions\\\\ t=2.07915, \:t=0.42084$

Rounding off we get,

t = 2.08 , t = 0.42

Thus the first time when the ball will reach a height of 20 feet is 0.42 seconds

4 0

3 years ago