Answer:
Below
Step-by-step explanation:
X(x+10)=36
x= -5+sqrt 61 or-5-sqrt 61
since only the first one bigger than0, x is -5+sqrt61 and other side is sqrt61+5
Answer:
$71.40
Step-by-step explanation:
Turn the percentage 30 to a decimal, which is 0.3 then multiply it by 238 to get 71.4
False, this statement is not true, because if you change the parenthesis, it means that you will do that thing first (PEMDAS)
Therefore, the sstatement is false, because the answers will be completely different,
hope this helps
M(CXA) = m(BXA) + m(CXB)
= 30°20' + 40°35'
m(CXA) = 70°55'
Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that
<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>
<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>
where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.
Then the sum is
<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>
and its magnitude is
||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)
… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))
… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))
… = √(16 + 16 cos(135° - 45°) + 4)
… = √(20 + 16 cos(90°))
… = √20 = 2√5
