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2 years ago

11

The local service center advertises that it charges a flat fee of $50 plus $8 per mile to tow a vehicle. Write an equation that

represents the total cost (C) of a service for m miles of towing. Express your mathematical thinking.

2 answers:

Lorico [155]2 years ago

7 0

jshsjsjnhashsjsuhfjd

Oliga [24]2 years ago

5 0

An equation that could help is c=50+8m

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The blades of a windmill turn on an axis that is 35 feet above the ground. The blades are 10 feet long and complete two rotation

a_sh-v [17]

The correct option is (c) h = 10sin(π15t)+35.

The equations can be used to model h, the height in feet of the end of one blade, as a function of time, t, in seconds is h = 10sin(π15t)+35.

<h3>How do windmills rotate?</h3>

The blades of a turbine, which resemble propellers and function much like an airplane wing, capture the wind's energy.

A pocket of low-pressure air develops on one side of the blade when the wind blows. The blade is subsequently drawn toward the low-pressure air pocket, which turns the rotor.

Calculation for the equation of the model height-

Let's now review each choice individually and select the best one.

The blade is horizontal at time t = 0. As a result, h = 35 at t = 0 is valid for all of the possibilities in this situation.

They accomplish two spins in a minute. The blades will so complete one rotation in 30 seconds. and they will complete a quarter rotation in 15/2 seconds. Because of this, the blade will be vertically up from time t = 0 to t = 15/2. Its height in this instance should be 35 + 10 = 45 ft. Let's now examine the available possibilities.

If we put t=15/2 in the options

Option (a) gives h = 25

Option (b) gives h = -10sin(15/2) + 35

Option (c) gives h = 45

Option (d) gives h = 10sin(15/2) + 35

Therefore, the correct equation is given in option c.

To know more about windmill, here

brainly.com/question/2031508

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The complete question is -

The blades of a windmill turn on an axis that is 35 feet above the ground. The blades are 10 feet long and complete two rotations every minute. Which of the following equations can be used to model h, the height in feet of the end of one blade, as a function of time, t, in seconds? Assume that the blade is pointing to the right, parallel to the ground at t = 0 seconds, and that the windmill turns counterclockwise at a constant rate.

a) h = −10sin(π15t)+35

b) h = −10sin(πt)+35

c) h = 10sin(π15t)+35

d) h = 10sin(πt)+35

6 0

2 years ago

3. (3 Points) A car covers a distance of 60 km in 30 minutes whereas a train

garri49 [273]

The car is faster because it’s 120km/hr, wile the train is 75km/hr

6 0

2 years ago

In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any

Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

$E \cap F = \emptyset,\quad E \cup F = \Omega$

where $\Omega$ is the whole sample space.

This implies that

$P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)$

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day $d_1$ .

The second footballer can be born on any other day, so he has 364 possible birthdays:

$d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}$

the probability for the first two footballers to be born on two different days is thus

$1 \cdot \dfrac{364}{365} = \dfrac{364}{365}$

Similarly, the third footballer can be born on any day, except $d_1$ and $d_2$ :

$d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}$

so, the probability for the first three footballers to be born on three different days is

$1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}$

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

$\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

So, the probability that at least two footballers are born on the same day is

$1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

since the two events are complementary.

8 0

3 years ago

n a 12 ounce bag of trail mix you notice that there are 18 M&Ms. You now purchase a 20 ounce bag of trail mix. How many M&am

Maslowich

30 M&Ms

1) Gathering the data

12-ounce bag of trail mix = 18 M&Ms

20-ounce bag=?

2) Assuming that the M&Ms are placed in following a constant rate we can write the following proportion:

12 --------------- 18

20 --------------- y

<em>Cross multiplying it due to the first property of proportions</em>

<em />

12y =20 x 18

12y = 360

y=30

3) So, I'd expect to find 30 M&Ms at a 20-ounce bag of trail mix.

6 0

1 year ago

Solve: 2.3 = v + 0.47 v = _____

ivanzaharov [21]

Answer:

2.3=v+0.47v=

We move all terms to the left:

2.3-(v+0.47v)=0

We add all the numbers together, and all the variables

-(+1.47v)+2.3=0

We get rid of parentheses

-1.47v+2.3=0

We move all terms containing v to the left, all other terms to the right

-1.47v=-2.3

v=-2.3/-1.47

v=1+0.83/1.47

7 0

2 years ago

Read 2 more answers