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anzhelika [568]
3 years ago
14

Select the correct answer from the drop-down menu.

Computers and Technology
1 answer:
Eva8 [605]3 years ago
3 0

Answer:

1. diagraph

2.analog

maybe

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What should be included in research for a problem statement? Select all that apply
Burka [1]

Answer:

I think the answer is C and D

7 0
3 years ago
Read 2 more answers
You are given a 11-bit floating point representation with 1-sign bit, 3 bits for the exponent, and 7-bits for the mantissa. Expr
qwelly [4]

Answer:

Sign Bit = 0 (for Positive number)

Exponent = 111 (Three Bit) calculated in step 5

Mantissa = 1111 11 0 (7 bits for mantissa)

the answer is

<em>sign bit -   Exponent -     Mantissa</em>

The representation of 15.75 in binary in 11 bits is given as

<em>0 - 111 - 1111 11 0</em>

<em></em>

Explanation:

Given data  

15.75 in decimal

calculate it in binary.

1.          

15/2 = 7 (Quotient)   and 1 (remainder)

7/2 = 3 (Quotient)     and 1 (remainder)

3/2 = 1 (Quotient)     and 1 (remainder)

by arranging them in order

<em>15 in decimal = 1111 in binary</em>

<em />

<em>2.</em>

<em />

<em>Now convert 0.75 by dividing 2 , </em>

multiplying = integer + fractional part;

1) 0.75 × 2 =  1.5 = <em><u>1</u></em> + 0.5;

2) 0.5 × 2 = 1= <u><em>1 </em></u>+ 0;

<em>so</em>

<em>0.75 in decimal = 0.11 in binary</em>

<em />

<em>3. </em>Because it is the 15.75 is positive number so we add 0 in extreme right as

<em> 15.75 =  0  1111 . 11</em>

<em>4.  Now making it normalize as by moving point</em>

<em />

0.1111 11 x 2^4

so exponent is 4.

<em />

<em>5. As exponent is 3 bits </em>

exponent + 2^ (No of bits-1) -1

4+ 2 ^ (3-1) - 1 =  4+4 -1 = 8-1 = 7

Now divide 7 by 2

<em>so </em>

7/2 = 3 (Quotient)     and 1 (remainder)

3/2 = 1 (Quotient)     and 1 (remainder)

<em>so exponent in bits is 111</em>

<em>6. Now calculate mantissa</em>

Just remove the point from 0.1111 11 as 1111 11

Now add rest of the bits 0 at right side

mantissa = 1111 11 0

<em />

<em />

<em></em>

8 0
3 years ago
C++ code pls write the code
Mariana [72]

Answer:

Following are the code to this question:

#include<iostream>//defining header file

using namespace std;

class vec//defining class vec  

{

int x, y, z; //defining integer varaible x, y, z

public: // using public access specifier

vec() //defining default constructor

{

   x = 0; //assign value 0 in x variable  

   y = 0; //assign value 0 in y variable

   z = 0;//assign value 0 in z variable

}

vec(int a, int b , int c) //defining parameterized constructor vec

{

   x = a; //assign value a in x variable

   y = b; //assign value b in y variable

   z = c;//assign value c in z variable

}

void printVec() //defining a method printVec

{

   cout<<x<<","<<y<<","<<z<<endl; //use print method to print integer variable value

}

//code

vec& operator=(const vec& ob) //defining operator method that create object "ob" in parameter  

{

x=ob.x; //use ob to hold x variable value

y=ob.y;//use ob to hold y variable value

z=ob.z;//use ob to hold z variable value

return *this;//using this keyword to return value  

}

};

int main()//defining main method

{

vec v(1,2,3);//calling parameterized constructor

vec v2; //creating class object to call method

v2=v; //creatring reference of object

v2.printVec(); //call method printVec

return 0;

}

Output:

1, 2, 3

Explanation:

In the above-given code part, a method "operator" is defined, that accepts an object or we can say that it is a reference of the class "ob", which is a constant type. Inside the method, the object is used to store the integer variable value in its variable and use the return keyword with this point keyword to return its value.    

6 0
3 years ago
What is the web page path on the web server for the URL:
Goshia [24]

Answer:

C: main/index.html

Explanation:

4 0
3 years ago
Susan is in charge of the inventory reports for her company.She will need to find specific inventory items as well as project in
Nezavi [6.7K]

Answer:

lookup function

Explanation:

We can use the lookup function to find some values or reference in a range, we can use this syntax: LOOKUP( value, lookup_range, [result_range] ), where value is what we are going to look for, lookup_range is the single row or column is the range, and result_range is an optional part, in this range we're going to get the value.

8 0
4 years ago
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