Answer:
No you do not need a interent browzer to get to the internet.
Explanation:
Answer:
The worst case running time of a linear search is O(N).
Explanation:
In a linear search, you will run the program looking at each array position until you find your desired information.
The best case scenario is when you find it at the first position.
The worst case scenario is when you find the value at the last array position. So, in a N-length array, the information is at position N. This means that the worst case running time of a linear search is O(N).
Explanation:
it is false because it is not appropriate
Answer:
void mn(int m, int n){
int sum = 0;
int count = 0;
if(m<n){
for(int i = m;i<=n;i++){
sum+=i;
}
}
else{
for(int i = n;i<=m;i++){
sum+=i;
}
}
count = abs(m - n)+1;
cout<<"Sum: "<<sum<<endl;
cout<<"Average: "<<(float)sum/count;
}
Explanation:
This line defines the method
void mn(int m, int n){
This initializes sum and count to 0
int sum = 0;
int count = 0;
This checks if m is less than n
if(m<n){
This iterates from m to n and calculates the sum of numbers between this interval
<em> for(int i = m;i<=n;i++){</em>
<em> sum+=i;</em>
<em> }</em>
<em> }</em>
If otherwise,
else{
This iterates from n to m and calculates the sum of numbers between this interval
<em> for(int i = n;i<=m;i++){</em>
<em> sum+=i;</em>
<em> }</em>
<em> }</em>
This calculates the range from m to n using absolute function
count = abs(m - n)+1;
This prints the calculated sum
cout<<"Sum: "<<sum<<endl;
This calculates and prints the average
cout<<"Average: "<<(float)sum/count;
}
<em>See attachment for complete program that includes the main (in c++)</em>
Answer:
See explaination
Explanation:
public class Circle {
private double radius;
private Location location;
private String name;
/* (non-Javadoc)
* atsee java.lang.Object#hashCode()
*/
atOverride
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((location == null) ? 0 : location.hashCode());
long temp;
temp = Double.doubleToLongBits(radius);
result = prime * result + (int) (temp ^ (temp >>> 32));
return result;
}
/* (non-Javadoc)
* atsee java.lang.Object#equals(java.lang.Object)
*/
atOverride
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Circle other = (Circle) obj;
if (location == null) {
if (other.location != null)
return false;
} else if (!location.equals(other.location))
return false;
if (Double.doubleToLongBits(radius) != Double.doubleToLongBits(other.radius))
return false;
return true;
}
NOTE: Replace all the "at" within the program with the at symbol ie shift 2.
