Answer:
3y+1
Step-by-step explanation:
4y+3-y-2
3y+3-2
3y+1
Answer:
Option 2: (1, 0) and (0, -5)
Step-by-step explanation:
Let's solve this system of equations using the elimination method.
Start by labelling the two equations.
5x -y= 5 -----(1)
5x² -y= 5 -----(2)
(2) -(1):
5x² -y -(5x -y)= 5 -5
Expand:
5x² -y -5x +y= 0
5x² -5x= 0
Factorise:
5x(x -1)= 0
5x= 0 or x -1= 0
x= 0 or x= 1
Now that we have found the x values, we can substitute them into either equations to solve for y.
Substitute into (1):
5(0) -y= 5 or 5(1) -y= 5
0 -y= 5 or -y= 5 -5
y= -5 or -y= 0
y= 0
Thus, the solutions are (0, -5) and (1, 0).
Answer:
7c^2d-7c+4d-10
Step-by-step explanation:
Start off with the term that has c^2 in it. 5c^2d + 2C = 7c^2d, then since you have multiple choice, the d value differs between the two answer choices that have 7c^2d so you can do +3d +d to get +4d to get the fourth answer choice.
To check your work, you can add/subtract each term to see if you get 7c^2d-7c+4d-10
Number 1 a and d are true
number to its b c and d
number 3 idk, sorry
Just replace X with the given value.
X = -3
f(-3) = 5 - (-3)
f(-3) = 5 +3
f(-3) = 8
