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LenKa [72]
3 years ago
14

2 similar cardboards have areas of 24cm square and 150cm square. if the length of the bigger one is 10cm, what is the length of

the smaller one​
Mathematics
2 answers:
kondaur [170]3 years ago
8 0

Answer:

1,6

Step-by-step explanation:

150:10=15

24:15=1,6

-BARSIC- [3]3 years ago
8 0

Answer:

4 cm

Step-by-step explanation:

Given 2 similar figures with sides in ratio a : b , then

ratio of areas = a² : b²

let n be the length of the smaller one , then

ratio of sides = n : 10

ratio of areas = n² : 10² = n² : 100

Using proportion

( \frac{ratio}{area} )

\frac{n^2}{24} = \frac{100}{150} = \frac{2}{3} ( cross- multiply )

3n² = 48 ( divide both sides by 3 )

n² = 16 ( take the square root of both sides )

n = \sqrt{16} = 4

length of the smaller one is 4 cm

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What is mean of 8,3,3,7 and 4
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The mean is the average of the numbers. To obtain it, you add all the numbers together and divide by the number of numbers. So:

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Which of the following functions is graphed below?
elixir [45]

Answer: What are the options for the functions?

Step-by-step explanation:

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3 years ago
Mark has a yard in the shape shown the area of his yard is 100 square meters the bottom side (base) is 20 meters what is the dis
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3 years ago
A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th
NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

A = a + (A \cap B)

In which a is the probability that he wins the first race but not the second and A \cap B is the probability that he wins both these races.

By the same logic, we have that:

B = b + (A \cap B)

The probability that he wins both races is 0.5.

This means that A \cap B = 0.5

The probability that he wins the second race is 0.6

This means that B = 0.6

B = b + (A \cap B)

0.6 = b + 0.5

b = 0.1

The probability that he wins the first race is 0.7.

This means that A = 0.6

A = a + (A \cap B)

0.7 = a + 0.5

a = 0.2

A) he wins at least one race.

This is

P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

P = a + b = 0.2 + 0.1 = 0.3

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0
3 years ago
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