Answer: 15e^5x
Step - by - step
y=3e^5x - 2
By the sum rule, the derivative of 3e^5x - 2 with respect to x is d/dx [ 3e^5x ] + d/dx [-2].
d/dx [ 3e^5x ] + d/dx [ -2 ]
Evalute d/dx [ 3e^5x ]
Since 3 is constant with respect to x , the derivative of 3e^5x with respect to x is
3 d/dx [ e^5x ].
3 d/dx [ e^5x ] + d/dx [ -2 ]
Differentiate using the chain rule, which states that d/dx [ f(g(x))] is f' (g(x)) g' (x) where f(x) = e^x and g(x) = 5x.
To apply the Chain Rule, set u as 5x.
3 ( d/du [ e^u] d/dx [5x] ) + d/dx [ -2]
Differentiate using the Exponential rule which states that d/du [ a^u ] is a^u ln(a) where a=e.
3( e^u d/dx[5x] ) + d/dx [ -2 ]
Replace
3(e^5x d/dx [5x] ) + d/dx [ -2 ]
3(e^5x( 5 d/dx [x] )) + d/dx [ -2 ]
Diffentiate using the Power Rule which states that d/dx [x^n] is nx^n-1 where n=1.
3(e^5x(5*1)) + d/dx [-2]
3 ( e^5x * 5 ) + d/dx [-2]
Multiply 5 by 3
15e^5x + d/dx [-2]
Since -2 is constant with respect to x, the derivative of -2 with respect to x is 0.
15e^5x + 0
15e^5x
Answer:
the answer I'd 1.008
Step-by-step explanation:
mark as brainliest:)
Slope of AB = 1/3 and slope of BC = -3 so these 2 lines are perpendicular
The same is true for all the other adjjacent pairs of lines.
Oppoitse lines are also paralllel ( slope of AB = 1/3 and slope of DC = 1/3) and other pair are both of slope -3.
So Its C
So.
.
Let's get started with formulas.
.
I KNOW you hate formulas!! So do I, but we have to use them. No "buts".
.
So, how many minutes are in 2 weeks?
.
Search it up. For your convenience, it is 20,160 minutes.
.
Well, I think you have your answer, since each quiz is 5 minutes, 5 times 50 (5 x 50) is 2,500 minutes.
.
Yes, you can do 50 quizzes and MUCH MUCH more in 2 weeks.
.
Hope I helped!!
74 cause an absolute value of any number will always be positive.
