Answer: y=8 m=5
Step-by-step explanation:
It’s should be 12.04 after you do all the math and add it up
X^-n = 1/x^n
Your fraction becomes:
1/ {(m^5 t^2)(27m^6t^3)} now combine the powers in the denominator
1/ (27 m^11 t^5)
If tan theta is -1, we know immediately that theta is in either Quadrant II or Q IV. We need to focus on Q IV due to the restrictions on theta.
Because tan theta is -1, the ray representing theta makes a 45 degree angle with the horiz axis, and a 45 degree angle with the negative vert. axis. Thus the hypotenuse, by the Pythagorean Theorem, tells us that the hyp is sqrt(2).
Thus, the cosine of theta is adj / hyp, or +1 / sqrt(2), or [sqrt(2)]/2
The secant of theta is the reciprocal of that, and thus is
2 sqrt(2)
---------- * ------------ = sqrt(2) (answer)
sqrt(2) sqrt(2)
Answer:
m∠1=103°
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
An exterior angle of a triangle is equal to the sum of the opposite interior angles
so
In this problem
m∠1=m∠2+m∠3
substitute the given values
m∠1=31°+72°=103°
