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3 years ago

Estimate the unit rate. 283 students in 11 classes

Mathematics

1 answer:

Archy [21]3 years ago

5 0

Answer:

So estimate.

Really depends on what needs to be estimated, the answer or the overall equation.
So doing the real one first.
283/11 = 25 8/11

You can’t have “part” of a student so rounding this you can go up since 8 is more then half of 11

So 26 students

If you were to round the overall equation then you’d get
280 / 10 which is 28 students per class

So two options.

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A manufacturer of cheese filled ravioli supplies a pizza restaurant chain. Based on data collected from its automatic filling pr

kolbaska11 [484]

Answer:

A.0.39 grams

margin of error at 90% confidence intervals is

M.E = 0.39 grams

Step-by-step explanation:

Explanation:-

Given a sample of size n = 25

mean of the sample x⁻ = 15 grams

Standard deviation of the sample 'S' = 1.5 grams

margin of error at 90% confidence intervals is determined by

$Margin error = \frac{t_{0.90} S.D}{\sqrt{n} }$

The degrees of freedom ν = n-1 = 25-1 =24

The tabulated value t₀.₉₀ = 1.318

$Margin error = \frac{1.318X 1.5}{\sqrt{25} }$

Margin of error = 0.3954

Conclusion:-

Margin of error at 90% confidence intervals = 0.3954

4 0

4 years ago

What are the coordinates of the x-intercept and y-intercept of the line -y-2x=4

Archy [21]

I hope it helps you get it right right

3 0

3 years ago

Help with length of hypotenuse

Salsk061 [2.6K]

Answer:

sqrt(10) *x

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2

x^2 + (3x)^2 = hypotenuse ^2

x^2 + 9x^2 = hypotenuse ^2

10x^2 = hypotenuse ^2

Take the square root of each side

sqrt( 10x^2) = sqrt(hypotenuse ^2)

sqrt(10) * x = hypotenuse

5 0

3 years ago

Read 2 more answers

Karen wants to advertise how many chocolate chips are in each big chip cookie at her bakery. she randomly selects a sample of 69

Tomtit [17]

Answer: $(10.1989,\ 11.0011)$

Step-by-step explanation:

Given : Sample size : n=69

Sample mean : $\overline{x}=10.6$

Standard deviation : $s=1.7$

Significance level : $\alpha:1-0.95=0.05$

Then , Critical value : $z_{\alpha/2}=1.96$

The formula to confidence interval is given by : -

$\overline{x}\pm z_{\alpha/2}\dfrac{s}{\sqrt{n}}\\\\\Rightarrow\ 10.6\pm (1.96)\dfrac{1.7}{\sqrt{69}}\\\\\approx10.6\pm0.4011=(10.6-0.4011,10.6+0.4011)=(10.1989,\ 11.0011)$

Hence, the 95% confidence interval for the number of chocolate chips per cookie for big chip cookies= $(10.1989,\ 11.0011)$

8 0

4 years ago

The fundraising group collected the quarters from the school's wishing well. The group arranged the quarters into 8 piles and of

Mariulka [41]

8•20=q. Multiply the number of piles by the number of quarters in each pile: 8•20=160, there were 160 quarters. Now to find how much they made multiply the number of quarters by how much 1 quarter is: 160•.25=40 they made $40 :)

7 0

3 years ago