Answer:
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know:</h3>
- linear equation
- linear equation word problems
- PEMDAS
<h3>tips and formulas:</h3>
<h3>let's solve:</h3>
all we need to care about the middle condition which is
<h3>the new test score is 15 points more than the original score</h3>
given that
original score is x
New score is y
if you pay attention to the given condition
we can find it same as linear equation
therefore
according to the question
the equation is
<h2>y=x+15</h2>
Answer:
I believe the answer is B
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
c. j = a + 5
such that 7 = 2 +5
1000 g = 1 kg
2500 g = 2,5 kg
The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
f(2.1) = 48(2.1)-16(2.1)^2 = 30.25
etc.
f(2.05) = 31.16
f(2.01) = 31.8384
Now plug these values into the formula
(20-32)/0.5 = -24
(30.25-32)/0.1 = -17.5
etc.
= -16.8
= -16.16
Final answer:
2.5s => -24 ft/s
2.1s => -17.5 ft/s
2.05 => -16.8 ft/s
2.01 => -16.16 ft/s
Hope I helped :)
