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2 years ago

What is the solution to this question? Plz help thx.

Mathematics

2 answers:

IRISSAK [1]2 years ago

4 0

Hope you could understand.

If you have any query, feel free to ask.

Brilliant_brown [7]2 years ago

3 0

$\huge \sf \frac{9x^{2} }{4y }$

<em>Refer to the attachment!!~</em>

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A stadium has central rectangular area 125m long by 80 m wide there are two semicircular ends.running tracks goes all way round

olga_2 [115]

) Using formula for cicumference.

Circumference = Pi * diameter

Circumference = Pi * 80m

Circumference = 251.2m.

Total inside length of the curved ends.

2)Total distance round inside of track =

2(125) + 251.2m

= 250 + 251.2

= 501.2m

3) Area of circular ends =

Pi*r^2

= Pi*40^2

= 5024m^2

Area of central area (rectangle)

length * width

125m * 80m

= 10,000m^2

Total area inside track =

5,024m^2 + 10,000m^2

= 15,024m^2

Hope this helps.

:-)

7 0

3 years ago

Please help. Thank you

Inessa [10]

Given:

$PQRS\sim TUVW$

In the given figure, PS=x, RS=35, UV=20, VW=25 and TW=15

To find:

The scale factor from PQRS to TUVW.

Solution:

We have,

$PQRS\sim TUVW$

We know that the corresponding sides of similar figures are proportional. The scale factor is the ratio of one side of image and corresponding side of preimage.

The scale factor is:

$k=\dfrac{VW}{RS}$

$k=\dfrac{25}{35}$

$k=\dfrac{5}{7}$

Therefore, the scale factor from PQRS to TUVW is $k=\dfrac{5}{7}$ .

6 0

3 years ago

1) Last Tuesday, Regal Cinemas sold a total of 85 movie tickets. Ticket sales totaled

irakobra [83]

In this question, some of the data is missing so its a complete question and the solution can be defined as follows:

$\bold{\text{m = matinee tickets}} \\\\\bold{\text{s = student tickets}}\\\\\bold{\text{r = regular tickets}}$

By given question, calculating equations are:

$\to \bold{m + s + r = 8500}............................................(a)\\\\\to \bold{5m + 6s + 8.50r = 64600}............................(b)\\\\\to \bold{s = 2m}...................(c)$

Putting the equation (c) value in the equation (a) to calculate value:

$m + 2m + r = 8500\\\\3m + r = 8500\\\\r = 8500 - 3m........................................(d)$

Putting equation (c) and (d) value into equation (b):

$5m + 6(2m) + 8.50(8500 - 3m) = 64600\\\\5m + 12m + 72250 - 25.50m = 64600\\\\-8.50m = 64600 - 72250 \\\\-8.50m = -7650\\\\m = \frac{-7650}{-8.50}\\\\m = \frac{7650}{8.50}\\\\m = 900$

Putting m value into equation (c) and equation (d) to calculate its value:

Calculating the s value:

$\to s = 2(900) \\\\ \to s = 1800$

Calculating the r value:

$\to r = 8500 - 3(900) \\\\\to r = 8500 - 2700\\\\\to r = 5800\\\\$

So, the final value of "m, s, and r" are "900, 1800, and 5800".

Learn more:

brainly.com/question/2929577

7 0

3 years ago

Plz help ASAP

DENIUS [597]

A+c = 150
10.25a+7.75c = 1470

4 0

3 years ago

Plz show work ☺ and plz explain

dolphi86 [110]

You HAVE to use Pemdas.
2[3(4^2+1)]-2^3
2(3(16+1))-2^3
2(3(17))-2^3
2*51-2^3
102-8
94.

Explanation: you use Pemdas P-parenthesis
E-exponents
M-multiplication
D-division
A-addition
S-subtraction

3 0

3 years ago

Read 2 more answers