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1 year ago

Help please quick! Plato

Mathematics

1 answer:

Radda [10]1 year ago

8 0

Answer:

Step-by-step explanation:

The function (f+g)(x) is the sum of the two functions:

(f+g)(x) = f(x) +g(x) = (ln(2x) -15) +(3sin(x) -7)

= ln(2x) +3sin(x) +(-15 -7)

(f+g)(x) = ln(2x) +3sin(x) -22

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Please Help!

MAVERICK [17]

For a translation of 4 units right, the graph will become -3(x-4). the 4 is negative to indicate that the translation is right.
For a vertical stretch of 4, the graph will become 4x-3(x-4)=-12(x-4).

With this information, g(x)=-12(x-4)

5 0

2 years ago

A runner increased her distance from 9 miles to 12.5 miles a week. Find the percent increase in mileage.

kondor19780726 [428]

Answer:

39 percent is increase in mileage.

Thus, the correct option is B. 39%.

Step-by-step explanation:

Given:

A runner increased her distance from 9 miles to 12.5 miles a week.

Now, to find percent increase in mileage.

Previous mileage = 9 miles.

Present mileage = 12.5 miles.

Mileage increase = 12.5 - 9 = 3.5 miles.

Now, to get the percent increase in mileage:

$\frac{Mileage\ increased}{previous\ mileage} \times 100$

$=\frac{3.5}{9} \times 100$

$=\frac{350}{9}$

$=38.88\%.$

Approximately the percent increase = 39%.

Therefore, 39% is increase in mileage.

Thus, the correct option is B. 39%.

4 0

2 years ago

Damian is working two summer jobs, making $9 per hour babysitting and making $14 per hour clearing tables. In a given week, he c

LenaWriter [7]

Answer:

5656

Step-by-step explanation:

3 0

2 years ago

2. Which of the functions below is an inverse of the quadratic function f(x) = x2 - 3 ?

mezya [45]

Answer:

the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

Step-by-step explanation:

We need to find inverse of the quadratic function $f(x) = x^2 - 3$

Let

$y=x^2-3$

Replace x and y

$x=y^2-3$

Now, we will solve for y

Adding 3 on both sides

$x+3=y^2-3+3$

$x+3=y^2$

Taking square root on both sides

$\sqrt{y^2}=\sqrt{x+3}\\y=\pm \sqrt{x+3}$

Now replace y with $f^{-1}(x)$

$f^{-1}(x)=\pm \sqrt{x+3}$

So, the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

3 0

2 years ago

What ordered pairs are solutions for the equation y=-2x+5

Shalnov [3]

Answer:

( 0 , 5 ) , ( 1 , 3 ) ( 2 , 1 )

Step-by-step explanation:

1. x=0

y=-2(0)+5

y=5

( 0 , 5 )

2. x=1

y=-2(1)+5

y=-2+5

y=3

( 1 , 3 )

3. x=2

y=-2(2)+5

y=-4+5

y=1

( 2 , 1 )

4 0

2 years ago