Answer:
look up desmos graphing calculator! you're welcome x
Step-by-step explanation:
They are all eawualateral
1. Let's call:
x: the width of the walkway.
b: 2x+16 (there is a widht "x" of the walkway on each side).
h: 2x+32 (there is a widht "x" of the walkway on each side).
A: 924 ft^2 ( the area of the pool of including the walkway).
2. The area of a rectangle is:
A=(b)(h)
b: the base of the rectangle (2x+16)
a: the height of the rectangle (2x+32)
3. Then, we have a quadratic equation:
924=(2x+16)(2x+32)
4x^2+64x+32x+512-924=0
4x^2+96x-412=0
4. We apply the quadratic formula to find the value of "x":
x=(-b±√(b^2-4ac))/2a
x=3.71
The answer is: The width of the walkway is 3.71 ft
The correct answer is Choice B: 53.0 feet.
If you draw a picture of the cross section, you will have a right triangle. The hypotenuse is 58 and one of the legs is 23.6. All you have to do is use the Pythagorean Theorem and solve for the missing side.
x^2 + 23.6^2 = 58^2
Answer:
Minimum - 8.1 inches
Maximum - 8.35 inches
Step-by-step explanation:
The specifications for manufacturing a steel rod stipulate that the length must be 8.225 ± 0.125 inches.
This means that the minimum length must not be 0.125 inches less than 8.225 inches and the maximum length must not be 0.125 inches greater than 8.225 inches.
The minimum length is therefore:
8.225 - 0.125 = 8.1 inches
The maximum length is therefore:
8.225 + 0.125 = 8.35 inches
