Write an equation for each slope following the formula: y=mx+b

A bag contains 4 b l u e marbles, 3 w h i t e marbles, and 10 r e d marbles. If a marble is drawn from the bag, replaced, and an

lawyer [7]

Answer:

40/289

Step-by-step explanation:

We can see these two events are independent as Regina replaced marble after drawing one marble.

We can find possible outcomes by adding number of blue, red and yellow marbles.

possible outcomes= 4+3+10= 17

Let us find probability of getting a blue marble on first draw.

$P( blue\ marble)= \frac{4}{4+3+10} = \frac{4}{17}$

Now we will find probability of getting red marble.

$P(red/marble)= \frac{10}{17}$

We can find probability of getting a blue marble and then red marble by multiplying both probabilities.

$P(\text{ Blue then red})=\frac{4}{17}* \frac{10}{17} =\frac{40}{289}$

4 0

3 years ago

Eric and Bryan live next door to each other and are best friends. They love to play PlayStation each afternoon after school. Eri

maxonik [38]

Answer:

6; 54 is 6 times 9

Step-by-step explanation:

9x = 54

x = 54/9

x = 6

6 0

2 years ago

Urgent. There are 12 coloured counters in a bag. The counters are black, white or grey A counter is chosen at random. The probab

Nastasia [14]

Answer:

1/12

Step-by-step explanation:

Needed information

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

The sum of the probabilities of all outcomes must equal 1

Solution

We are told that the probability that the counter is not black is 3/4.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is black by subtracting 3/4 from 1:

$\sf P(counter\:not\:black)=\dfrac34$

$\implies \sf P(counter\:black)=1-\dfrac34=\dfrac14$

We are told that the probability that the counter is not white is 2/3.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is white by subtracting 2/3 from 1:

$\sf P(counter\:not\:white)=\dfrac23$

$\implies \sf P(counter\:white)=1-\dfrac23=\dfrac13$

We are told that there are black, white and grey counters in the bag. We also know that the sum of the probabilities of all outcomes must equal 1. Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:

$\begin{aligned}\sf P(counter\:grey) & = \sf1-P(counter\:black)-P(counter\:white)\\\\ & =\sf 1-\dfrac14-\dfrac13\\\\ & = \sf \dfrac{12}{12}-\dfrac{3}{12}-\dfrac{4}{12}\\\\ & = \sf \dfrac{12-3-4}{12}\\\\ & = \sf \dfrac{5}{12}\end{aligned}$

7 0

2 years ago

How could I get rid of the 3 shown in equation 1?

Tems11 [23]

Answer:

Step-by-step explanation:

3 log 2+log (x-4)=log 2³+log (x-4)=log 8+log (x-4)=log 8(x-4)

8 0

3 years ago

. You invest £4000 in a fund which earns 11% compound return per year. How much would the fund be worth after 10 years, given th

zmey [24]

Answer: $5,678.85

Step-by-step explanation:

First find out how much the fund was worth after 5 years.

Compound interest formula:

= Investment * (1 + rate) ^ years

= 4,000 * ( 1 + 11%)⁵

= £6,740.23

Half was removed:

= 6,740.23/2

= £3,370.12

Then compound this for the remaining 5 years:

= 3,370.12 * (1 + 11%)⁵

= $5,678.85

7 0

3 years ago