Use two points to find the slope
The tangent to
at the point (0, 5) has a slope equal to the derivative evaluated at
.

This tangent passes through the point (0, 5), so its equation is

The normal line passes through the same point, but is perpendicular to the tangent line, so its slope is the negative reciprocal of the slope of the tangent. So the equation for the normal line is

Hey!
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Steps To Solve:
~Subtract n to both sides
3 - n = n + 4 - n
~Simplify
3 - n = 4
~Subtract 3 to both sides
3 - n - 3 = 3 - 4
~Simplify
n = -1
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Answer:

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Hope This Helped! Good Luck!