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2 years ago

For the polynomial f(x) = 5x^5 + 3x^3 - 16x + 2

Mathematics

1 answer:

mojhsa [17]2 years ago

3 0

I hope this helps you :)

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To pay for a sofa, Maddie made a payment of 64 dollars each month for one year. How much did the sofa cost ?

mario62 [17]

So you need to multiply 64 times 12 and she has to pay $768

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4 years ago

Read 2 more answers

If the temperature were to drop 38 degrees, which number would display this best?

emmasim [6.3K]

I think it might be -38, not 100% though.

3 0

3 years ago

For which values of p and q, will the following pair of linear equations have infinitely many

Tema [17]

In order to have infinitely many solutions with linear equations/functions, the two equations have to be the same;
In accordance, we can say:
(2p + 7q)x = 4x [1]
(p + 8q)y = 5y [2]
2q - p + 1 = 2 [3]
All we have to do is choose two equations and solve them simultaneously (The simplest ones for what I'm doing and hence the ones I'm going to use are [3] and [2]):
Rearrange in terms of p:
p + 8q = 5 [2]
p = 5 - 8q [2]
p + 2 = 2q + 1 [3]
p = 2q - 1 [3]
Now equate rearranged [2] and [3] and solve for q:
5 - 8q = 2q - 1
10q = 6
q = 6/10 = 3/5 = 0.6

Now, substitute q-value into rearranges equations [2] or [3] to get p:
p = 2(3/5) - 1
p = 6/5 - 1
p = 1/5 = 0.2

3 0

3 years ago

Write the equation of a line that passes through the points (4,6) and (−8,3)

kari74 [83]

Answer:

y= 1/4x+5

Step-by-step explanation:

y=mx+c

to calculate gradient: change in y/change in x

-3/-12 = 0.25

y = 1/4x+c

4 * 1/4 = 1

6-1 = 5

c= 5

Totally:
y= 1/4x+5

5 0

1 year ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$

95% of all values lie within the 1 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$

99.7% of all values lie within the 1 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

$\mu = 55\\\sigma = 4$

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$ = $(55-4,55+4)$ = $(51,59)$

95% of all values lie within the 2 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$ = $(55-2(4),55+2(4))$ = $(47,63)$

99.7% of all values lie within the 3 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$ = $(55-3(4),55+3(4))$ = $(43,67)$

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

4 0

3 years ago