Sample Response:<span> The value of </span>m<span> must be greater than the value of</span><span> n</span><span>. When you multiply the binomials, the middle term is the result of combining the outside and inside products. So, </span>bx<span> = –</span>nx<span> + </span>mx<span>, or </span>bx<span> = (–</span>n<span> + </span>m)x<span>. This means that </span>b<span> = –</span>n<span> + </span>m<span>. When adding numbers with opposite signs, you subtract their absolute values, and keep the sign of the number having the larger absolute value. Since </span>b<span> is positive, m </span><span>must have the larger absolute value</span>
Answer:
Step-by-step explanation:
We begin with m(x) = 3^x.
Then -m(x + 1) = -3^(x + 1). Here we've inserted the ' - ' sign and replaced x with (x + 1).
Answer:
The correct answer has already been given (twice). I'd like to present two solutions that expand on (and explain more completely) the reasoning of the ones already given.
One is using the hypergeometric distribution, which is meant exactly for the type of problem you describe (sampling without replacement):
P(X=k)=(Kk)(N−Kn−k)(Nn)
where N is the total number of cards in the deck, K is the total number of ace cards in the deck, k is the number of ace cards you intend to select, and n is the number of cards overall that you intend to select.
P(X=2)=(42)(480)(522)
P(X=2)=61326=1221
In essence, this would give you the number of possible combinations of drawing two of the four ace cards in the deck (6, already enumerated by Ravish) over the number of possible combinations of drawing any two cards out of the 52 in the deck (1326). This is the way Ravish chose to solve the problem.
Another way is using simple probabilities and combinations:
P(X=2)=(4C1∗152)∗(3C1∗151)
P(X=2)=452∗351=1221
The chance of picking an ace for the first time (same as the chance of picking any card for the first time) is 1/52, multiplied by the number of ways you can pick one of the four aces in the deck, 4C1. This probability is multiplied by the probability of picking a card for the second time (1/51) times the number of ways to get one of the three remaining aces (3C1). This is the way Larry chose to solve the this.
Step-by-step explanation:
To find the correct polynomial, we can use the answers to help us out. The middle variable must be the sum of +2 and another number; the last number in the equation must be the product of +2 and the other number.
Knowing this information, we can use the process of elimination to find the exact polynomial that contains the factor (3x + 2).
A) This can't be it because to get -x as the middle variable, you would need to add -3 and +2. However, -3 x +2 doesn't equal -4.
B) This equation isn't the right one because to get +8 you need to add +6 + 2. However, the product of these two isn't -8.
C) Can't be correct because +2 and -7 = -5, but 2 x -7 = -14...not -9.
D) Is the correct answer because you can add 2 and -1 to get +1. (There is an understood +1 in front of the x in the equation.) The product of 2 and -1 equals -2, which happens to be the last number inside this equation. Therefore, this (D) is the correct answer choice.
Hope I could help you out! If my math is incorrect, or I didn't provide the answer you were looking for, please let me know. However, if the answer was correct and well explained, please consider marking it <em>Brainliest</em>.
Have a good one!
God bless.