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3 years ago

BRAINLY PLS HELP ME ON THIS QUESTION!!!!

Mathematics

1 answer:

Allushta [10]3 years ago

5 0

Answer:

I'm pretty sure 10% of 82 is 8.2 and 60% of 82 is 49.2

If I'm wrong I'm sorry.......

Step-by-step explanation: I hope you have/had an amazing day<3

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After 3.5 hours ,pasha had traveled 217 miles if she travels at the constant speed how far will she have travelled after 4 hours

vesna_86 [32]

Answer:

248 miles

Step-by-step explanation:

we know that

After 3.5 hours ,Pasha had traveled 217 miles

using proportion

Find out how many miles she will have traveled after 4 hours

$\frac{3.5}{217}\ \frac{hours}{miles}=\frac{4}{x}\ \frac{hours}{miles}\\\\x=217(4)/3.5\\\\x=248\ miles$

4 0

4 years ago

Sphere and a cylinder have the same radius and height. The volume of the cylinder is 64 meters cubed.

Mrrafil [7]

Answer:

C. 128/3 meters cubed

Step-by-step explanation:

The volume of a cylinder is denoted by: $V=\pi r^2h$ , where r is the radius and h is the height. We know it's equal to 64, so we can set that equal to V:

$V=\pi r^2h$

$64=\pi r^2h$

We know that the sphere and cylinder have the same height and radius. However, the "height" of a sphere is actually the same as its diameter, which is twice its radius. Then, we can replace h in the above equation with 2r:

$64=\pi r^2h$

$64=\pi r^2*2r=2\pi r^3$

$\pi r^3=64/2=32$

Now, the volume of a sphere is denoted by: $V=\frac{4}{3} \pi r^3$ , where r is the radius. From above, we know that $\pi r^3=32$ , so we can plug this into the equation:

$V=\frac{4}{3} \pi r^3$

$V=\frac{4}{3} *32=128/3$

Thus, the answer is C.

4 0

3 years ago

Read 2 more answers

Find the slope of the line that passes through A(-2,-1), B(-1, 1)

Aleksandr [31]

Answer:

Slope: 2

Step-by-step explanation:

3 0

3 years ago

Write and simplify an expression for the perimeter of each figure

DedPeter [7]

Answer:

4d + 6c - 6

Step-by-step explanation:

The perimeter of the rectangle is the sum of all 4 sides

perimeter = 2d - 3 + 3c + 2d - 3 + 3c = 4d + 6c - 6

7 0

3 years ago

Read 2 more answers

Mathematical Statistics with Applications Homework Help

photoshop1234 [79]

7.37:

a. W follows a chi-squared distribution with 5 degrees of freedom. See theorem 7.2 from the same chapter, which says

$\displaystyle \sum_{i=1}^n\left(\frac{Y_i-\mu}{\sigma}\right)^2$

is chi-squared distributed with n d.f.. Here we have $\mu=0$ and $\sigma=1$ .

b. U follows a chi-squared distribution with 4 degrees of freedom. See theorem 7.3:

$\displaystyle \frac1{\sigma^2}\sum_{i=1}^n (Y_i-\overline Y)^2$

is chi-squared distributed with n - 1 d.f..

c. Y₆² is chi-square distributed for the same reason as W, but with d.f. = 1. The sum of chi-squared distributed random variables is itself chi-squared distributed, with d.f. equal to the sum of the individual random variables' d.f.s. Then U + Y₆² is chi-squared distributed with 5 + 1 = 6 degrees of freedom.

7.38:

a. Notice that

$\dfrac{\sqrt 5 Y_6}{\sqrt W} = \dfrac{Y_6}{\sqrt{\frac W5}}$

and see definition 7.2 for the t distribution. Since Y₆ is normally distributed with mean 0 and s.d. 1, it follows that this random variable is t distributed with 5 degrees of freedom.

b. Similar manipulation gives

$\dfrac{2Y_6}{\sqrt U} = \dfrac{\sqrt4 Y_6}{\sqrt U} = \dfrac{Y_6}{\sqrt{\frac U4}}$

so this r.v. is t distributed with 4 degrees of freedom.

4 0

3 years ago